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vaieri [72.5K]
2 years ago
3

A person is riding in a car traveling 89 km/h from west to east along the Earth’s equator. Earth rotates at this latitude at 167

0 km/h in the same direction as the car travels. Which statement applies to this scenario? Both a man beside the road and an astronaut on the moon will observe the speed of the person in the car at 89 km/h. A man beside the road will observe the speed of the person in the car at 89 km/h and an astronaut on the moon will observe the speed of the person at 1581 km/h. A man beside the road will observe the speed of the person in the car at 89 km/h and an astronaut on the moon will observe the speed of the person at 1759 km/h.
Physics
2 answers:
il63 [147K]2 years ago
5 0

Answer:

A man beside the road will observe the speed of the person in the car at 89 km/h and an astronaut on the moon will observe the speed of the person at 1759 km/h.

Explanation:

Given that, a person is riding in a car traveling 89 km/h from west to east along the Earth’s equator.

And also Earth rotates at this latitude at 1670 km/h in the same direction as the car travels.

Now, for an observer beside the road, earth is at rest as he also moves with earth at same speed.

⇒ relative speed of earth with respect to man on road is 0.

so, relative speed of person in ca is 89 km/h with respect to man beside road.

But now for an observer outside earth, the relative speed of earth is 1670 km/h and not 0. As he does not move with earth.

⇒ relative speed of person in car is 1670 + 89 = 1759 km/h with respect to astronaut. (here speeds are added because they move i same direction)

Andrew [12]2 years ago
3 0

Answer:

C. A man beside the road will observe the speed of the person in the car at 89 km/h and an astronaut on the moon will observe the speed of the person at 1759 km/h.

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A particle decelerates uniformly from a speed of 30 cm/s to rest in a time interval of 5.0 s. It then has a uniform acceleration
wel

Answer:

V=20cm/s

Explanation:

The average speed is the distance total divided the time total:

V=X/T

First stage:

T1=5s

v_{f}  =v_{o} - at

But, v_{f}  =0   (decelerates to rest)

then: a =v_{o} /t=0.3/5=0.06m/s^{2}

on the other hand:

x =v_{o}*t - 1/2*at^{2}=0.3*5-1/2*0.06*5^{2}=0.75m

X1=75cm

Second stage:

T2=5s

x =v_{o}*t + 1/2*at^{2}=0+1/2*0.1*5^{2}=1.25m

X2=125cm

Finally:

X=X1+X2=200cm

T=T1+T2=10s

V=X/T=20cm/s

8 0
2 years ago
A small smooth object slides from rest down a smooth inclined plane inclined at 30degrees horizontal.What is the acceleration do
asambeis [7]
The acceleration is given as:

a = g sin(30°) where g is the gravitational acceleration

For g = 10 m/s^2, we get

a = 10 sin(30°) = 10 * 1/2 = 5 m/s^2
7 0
2 years ago
Hoosier Manufacturing operates a production shop that is designed to have the lowest unit production cost at an output rate of 1
abruzzese [7]

Answer:

90.77%

its capacity utilization rate for the month is 90.77%

Explanation:

The capacity utilisation rate can be expressed mathematically as;

Capacity utilisation rate = capacity used/Best operating level × 100%

Given;

Total Number of production time = 205hours

Production output/capacity used = 21400 units

Best operation rate = 115units/hour

Best operation output for the month of July( at best operation level )

=115units/hour × 205 hours = 23575 units

Capacity utilisation rate = 21400/23575 × 100%

= 90.77%

3 0
2 years ago
1. What is the momentum of a golf ball with a mass of 62 g moving at 73 m/s?
Anit [1.1K]

Answer:

<h3>The answer is 4.53 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 62 g = 0.062 kg

velocity = 73 m/s

We have

momentum = 0.062 × 73 = 4.526

We have the final answer as

<h3>4.53 kgm/s</h3>

Hope this helps you

4 0
2 years ago
Plants use sunlight as energy to convert carbon dioxide and water into glucose and oxygen. Which best describes the reaction? Th
Alina [70]

Answer:

the correct statement is the first

The law of conservation of mass indicates the same amount of carbon will be found in the reactants as in the products.

Explanation:

The law of conservation of energy establishes that the masses are not destroyed, they can only be transformed.

Therefore the mass of carbon in the reactants (CO2 and H2O) must be in the products (glucose and oxygen)

so the correct statement is the first

The law of conservation of mass indicates the same amount of carbon will be found in the reactants as in the products.

6 0
2 years ago
Read 2 more answers
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