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Kruka [31]
2 years ago
14

A hydraulic press has one piston of diameter 2.0 cm and the other piston of diameter 16.0 cm. What force must be applied to the

smaller piston to obtain a force of 3200 N at the larger piston?
Physics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0

Answer:

<em>The force applied to the smaller piston = 2512 N</em>

Explanation:

Hydraulic press:  A hydraulic press is a device used to produce a very large force. A hydraulic force operates based on pascal's principle.

F/f = A/a................ Equation 1

making f the subject of the equation above

f =(F×a)/A............. Equation 2

Where F = Force on the larger piston, f = force on the smaller piston, A = area of the larger piston, a = area of the smaller piston.

<em>Given: F = 3200 N,  and</em>

<em>Area (A) = πD²/4 where D = 16.0 cm = 0.16 m</em>

<em>A = 3.143×(0.16)²/4 = 0.02 m²</em>

<em>Also</em>

<em>a = πd²/4 where d = 2 cm = 0.02 cm</em>

<em>a = 3.143×(0.02)²/4</em>

<em>a = 0.0157 m²</em>

<em>Substituting these values into equation 2</em>

<em>f = (3200×0.0157)/0.02</em>

<em>f = 2512 N</em>

<em>The force applied to the smaller piston = 2512 N</em>

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iren2701 [21]

The magnitude of the average force that the ball exerts against his glove is 600 N

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of ball = m = 0.15 kg

initial speed of ball = u = 40 m/s

final speed of ball = v = 0 m/s

distance = d = 20 cm = 0.2 m

<u>Asked:</u>

average force = F = ?

<u>Solution:</u>

<em>We will use </em><em>Newton's Law of Motion</em><em> to solve this problem as follows:</em>

F = m a

F = m (\frac { u^2 - v^2 } { 2d } )

F = 0.15 \times \frac { 40^2 - 0^2 } { 2 \times 0.2 }

F = 0.15 \times \frac { 1600 } { 0.4 }

F = 0.15 \times 4000

\boxed {F = 600 \texttt{ N}}

\texttt{ }

<h3>Learn more</h3>
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\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

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Answer:

Intensity of beam 18 feet below the surface is about 0.02%

Explanation:

Using Lambert's law

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then dI / I = kdt

taking log,

ln(I) = kt + ln C

I = Ce^kt

t=0=>I=I(0)=>C=I(0)

I = I(0)e^kt

t=3 & I=0.25I(0)=>0.25=e^3k

k = ln(0.25)/3

k = -1.386/3

k = -0.4621

I = I(0)e^(-0.4621t)

I(18) = I(0)e^(-0.4621*18)

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Solve the equation x=3logy2 for y.
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a) Average velocity: 2.8 m/s

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Explanation:

a)

The position of the car as a function of time t is given by

x(t)=\alpha t^2 - \beta t^3

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\beta = 0.05 m/s^3

The average velocity is given by the ratio between the displacement and the time taken:

v=\frac{\Delta x}{\Delta t}

The position at t = 0 is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

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The time interval is

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b)

The position at t = 0 is:

x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0

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c)

The position at t = 2 s is:

x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m

While the position at t = 4 s is:

x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m

So the displacement is

\Delta x = 20.8 - 5.6 = 15.2 m

While the time interval is

\Delta t = 4.0 - 2.0 = 2.0 s

So the average velocity is

v=\frac{15.2}{2.0}=7.6 m/s

Learn more about average velocity:

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