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insens350 [35]
2 years ago
4

The binary value of the ASCII letter "c" is 0110 0011. Using the handy chart that we learned in the lesson, convert this number

to its decimal value. You'll need to use some math for this question.
Mathematics
2 answers:
docker41 [41]2 years ago
8 0

Answer:The answer is c=99

Step-by-step explanation:

trust me pls

Marina CMI [18]2 years ago
6 0

Answer:

The decimal value is 99.

Step-by-step explanation:

We want to convert 01100011 to decimal.

We start counting the digit from the rightmost digit using zero-index system:

0 = 7

1 = 6

1 = 5

0 = 4

0 = 3

0 = 2

1 = 1

1 = 0

We multiply each digit by 2 having the index as power:

= (0 * 2^{7} ) + (1 * 2^{6} ) + (1 * 2^{5} ) + (0 * 2^{4} ) + (0 * 2^{3} ) + (0 * 2^{2} ) + (1 * 2^{1} ) + (1 * 2^{0} )\\= (0 * 128) + (1 * 64) + (1 * 32) + (0 * 16) + (0 * 8) + (0 * 4) (1 * 2) + (1 * 1)\\= 0 + 64 + 32 + 0 + 0 + 0 + 2 + 1\\= 99

Therefore, the decimal value of "c" is 99.

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A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The runnin
patriot [66]

Answer:

Option B is correct.

Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Step-by-step Explanation:

The clear, complete table For this question is presented in the attached image to this solution.

It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.

In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.

The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.

Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.

Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.

Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Hope this Helps!!!

7 0
2 years ago
Which fraction is equivalent to fraction with numerator 6 and denominator negative 8? fraction with numerator negative 8 and den
Rzqust [24]
Numerator is the the number above the line on a fraction, while the denominator is the number underneath the line. 

\frac{6}{-8} is similar to \frac{-6}{8}

Fraction with numerator -6 and denominator 8 
8 0
2 years ago
Read 2 more answers
Owen and his friend Kayden are going to a carnival that has games and rides. Owen played 5 games and went on 6 rides and spent a
djyliett [7]
Owen: 5x + 6y = $28.75
kayden; 4x + 3y= $16.25
that’s all i know, sorry
7 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
2 years ago
Lin has 13 coins in her pocket that equal 40 cents. All the coins are dimes, d, and pennies, p. Which combination of coins does
Luden [163]
To answer this question you should begin with the coin that has a higher value.  If you start with the dime and then just add the correct number of pennies to total $0.40, you will see that you will need 3 dimes ($0.30) and 10 pennies ($0.10).  

I used a guess and check strategy starting with 2 dimes.
7 0
2 years ago
Read 2 more answers
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