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garik1379 [7]
2 years ago
6

Which of the following numerical expressions gives the number of particles in 2.0 g of Ne?

Chemistry
1 answer:
mojhsa [17]2 years ago
7 0

Answer:

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

Explanation:

Step 1: Data give

Mass of Ne = 2.0 grams

Molar mass of neon = 20.18 g/mol

Number of Avogadro = 6.0 *10^23 /mol

Step 2: Calculate number of moles of neon

Moles Ne = Mass of ne / Molar mass of ne

Moles Ne = 2.0 / 20.18 g/mol

Moles Ne = 0.099 moles

Step 3: Calculate nulber of particles

Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22

Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

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A 60.0 mL solution of 0.112 M sulfurous acid (H2SO3) is titrated with 0.112 M NaOH. The pKa values of sulfurous acid are 1.857 (
djverab [1.8K]

Answer:

a)4.51

b) 9.96

Explanation:

Given:

NaOH = 0.112M

H2S03 = 0.112 M

V = 60 ml

H2S03 pKa1= 1.857

pKa2 = 7.172

a) to calculate pH at first equivalence point, we calculate the pH between pKa1 and pKa2 as it is in between.

Therefore, the half points will also be the middle point.

Solving, we have:

pH = (½)* pKa1 + pKa2

pH = (½) * (1.857 + 7.172)

= 4.51

Thus, pH at first equivalence point is 4.51

b) pH at second equivalence point:

We already know there is a presence of SO3-2, and it ionizes to form

SO3-2 + H2O <>HSO3- + OH-

Kb = \frac{[ HSO3-][0H-]}{SO3-2}

Kb = \frac{10^-^1^4}{10^-^7^.^1^7^2} = 1.49*10^-^7

[HSO3-] = x = [OH-]

mmol of SO3-2 = MV

= 0.112 * 60 = 6.72

We need to find the V of NaOh,

V of NaOh = (2 * mmol)/M

= (2 * 6.72)/0.122

= 120ml

For total V in equivalence point, we have:

60ml + 120ml = 180ml

[S03-2] = 6.72/120

= 0.056 M

Substituting for values gotten in the equation Kb=\frac{[HSO3-][OH-]}{[SO3-2]}

We noe have:

1.485*10^-^7=\frac{x*x}{(0.056-x)}

x = [OH-] = 9.11*10^-^5

pOH = -log(OH) = -log(9.11*10^-^5)

=4.04

pH = 14- pOH

= 14 - 4.04

= 9.96

The pH at second equivalence point is 9.96

4 0
2 years ago
Write the chemical symbol for the ion with 95 protons and 89 electrons.
qaws [65]
The element is Am and since you lose e- there must be a postive charge. Am+6 is the symbol
3 0
2 years ago
An unknown metal is dropped into 127 grams of water. The temperature of the water has been raised from 25OC to 28OC. Using the s
Gnesinka [82]

Answer:

he amount of heat gained by the water is 1.59 kJ    

Explanation:

Relation between heat energy, specific heat and temperature change is as follows

Q = mCΔT

where,    Q or q = heat energy

             m = mass

             C = specific heat  =4.186J/g°C

ΔT = (28°C - 25°C) = 3°C

Now, putting the given values into the above formula as follows.

Q = mCΔT

= 127 × 4.186 × 3

= 1594.86 J or 1.59 kJ    

Therefore, we can conclude that the amount of heat gained by the water is 1.59 kJ    

5 0
2 years ago
Ion arrangements of three general salts are represented below. h5sil917 h5sil917021 h5sil91703 which ion arrangement has the hig
vovangra [49]
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4 0
2 years ago
How many protons are there in 20.02 mol of neon (Ne)?
Anettt [7]
In order to determine the number of protons in 20.02 mol of Ne, we use Avogadro's number to convert the number of moles to number of atoms, 1 mol = 6.022 x 10^23 atoms. From there, we must know the number of protons in a Neon atom, which is 10. Thus, the formula will be:
(20.02 mol Ne)x(6.022 x 10^23 atoms/mol)x(10 protons/1 atom Ne) = 1.2056 x 10^26 protons 


7 0
2 years ago
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