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NemiM [27]
2 years ago
9

If a freely suspended vertical spring is pulled in downward direction and then released, which type of wave is produced in the s

pring?
Physics
2 answers:
Neko [114]2 years ago
4 0

Answer:longitudinal wave

Explanation:Longitudinal waves are types of wave in which the displacement of the medium is in the same direction as, the direction of propagation of the wave. Other example of wave is transverse wave

larisa [96]2 years ago
3 0

Answer:

longitudinal wave

Explanation:

it is perpendicular to the direction of the wave

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As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road i
Kitty [74]

Answer:

<em>B</em><em>.</em><em> </em><em>Kinetic</em><em> </em><em>friction</em><em> </em>

Explanation:

This is definitely the correct answer because kinetic friction acts when an object is in motion and it allows the object to move without slipping, etc

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6 0
2 years ago
Read 2 more answers
In the design of a timing mechanism, the motion of pin P in the fixed circular slot is controlled by the guide A, which is being
german

Answer: Got It!

<em>Explanation:</em> Guide A Starts From Rest With Pin P At The Lowest Point In The Circular Slot, And Accelerates Upward At A Constant Rate Until It Reaches A Speed Of 175 Mm/s At The ... In the design of a timing mechanism, the motion of pin P in the fixed circular slot is controlled by the guide A, which is being elevated by its lead screw.

6 0
2 years ago
A (1.25+A) kg bowling ball is hung on a (2.50+B) m long rope. It is then pulled back until the rope makes an angle of (12.0+C)o
daser333 [38]

Answer:

F = 0.535 N

Explanation:

Let's use the concepts of energy, at the highest and lowest point of the trajectory

Higher

   Em₀ = U = mg y

Lower

    Em_{f} = K = ½ m v²

    Emo =Em_{f}

    mg y = ½ m v2

    v = √ 2gy

   y = L - L cos θ

  v = √ (2g L (1-cos θ))

Now let's use Newton's second law n at the lowest point where the acceleration is centripetal

     F = ma

     a = v² / r

In turning radius is the cable length r = L

    F = m 2g (1-cos θ)

Let's calculate

    F = 2  1.25  9.8 (1 - cos 12)

    F = 0.535 N

   

7 0
2 years ago
A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a di
Vikentia [17]

Answer:

option B

Explanation:

given,

Force exerted by the hydraulic jack piston = F₁ = 250 N

diameter of piston, d₁ = 0.02 m

                                r₁ = 0.01 m

diameter of second piston,  d₂ = 0.15 m

                                r₂ = 0.075 m

mass of the jack to lift = ?

now,

    \dfrac{F_1}{A_1} =\dfrac{F_2}{A_2}

    \dfrac{250}{\pi r_1^2} =\dfrac{F_2}{\pi r_2^2}

    \dfrac{250}{0.01^2} =\dfrac{F_2}{0.075^2}

    F_2= \dfrac{250}{0.01^2}\times {0.075^2}

               F₂ = 14062.5 N

F = m g

m = \dfrac{F}{g}

m = \dfrac{14062.5}{9.8}

m = 1435 Kg

hence, the correct answer is option B

5 0
2 years ago
When the mass of the cylinder increased by a factor of 3, from 1.0 kg to 3.0 kg, what happened to the cylinder’s gravitational p
Gnesinka [82]

Answer:

It increased by a factor of 3.

Explanation:

The gravitational potential energy of an object is given by

U=mgh

where

m is the mass

g is the gravitational acceleration

h is the heigth of the object relative to some reference point (for instance, the ground)

As we see from the formula, the gravitational potential energy is directly proportional to the mass, m: therefore, if the mass of the cylinder is increased by a factor 3, then the gravitational potential energy will also increase by a factor 3.

6 0
2 years ago
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