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Pavlova-9 [17]
2 years ago
7

Jai Narayan sells two radio sets for 2288 each.

Mathematics
1 answer:
san4es73 [151]2 years ago
5 0

Answer:

1%

Step-by-step explanation:

S.P of each radio=$ 2288

Total S.P=2\times 2288=$4576

Gain=10%

Lose=10%

C.P=\frac{S.P\times 100}{100+gain(in\;percent)}

C.P=\frac{S.P\times 100}{100-loss(in\;percent)}

By using the formula

C.P of one radio=\frac{2288\times 100}{110}=$2080

C.P of another radio=\frac{2288\times 100}{100-10}=$2542.2

Total C.P of two radios=2080+2542.2=$4622.2

Total C.P >Total S.P

Loss=S.P-C.P

Loss=4622.2-4576=$46.2

Loss%=\frac{Loss}{C.P}\times 100

Loss %=\frac{46.2}{4622.2}\times 100=1%

Hence, his loss 1%

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Sunny_sXe [5.5K]

Answer:

a) W(t) = 371(1.168)^{t}

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Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

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W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

(1.168)^{t} = 1.61725

We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

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x^{2} =4804.9

\sqrt{x} ^{2}  = \sqrt{4804.9}

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