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storchak [24]
2 years ago
4

Which of the following is an engineering control used to safeguard against exposure to bloodborne pathogens? A. Sharp needles B.

Safety needles C. Reusable needles D. Uncapped needles
Physics
1 answer:
NARA [144]2 years ago
5 0

Answer:

B. Safety needles is the correct answer.

Explanation:

Bloodborne pathogens are transferred from one person to another by contaminated fluids or by blood and that causes infection in people.

Bloodborne pathogens are the pathogenic microbes present in the blood of humans that cause disease.

Examples: hepatitis B, human immunodeficiency virus, hepatitis C.

precaution need to follow against the bloodborne pathogen is

  • Use of ethanol rub for regular hand cleanliness.
  • Use personal protective equipment such as gloves, masks, and gowns.
  • Using safety needles.

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Human muscles have an efficiency of about __________. A. 9 to 17% B. 18 to 26% C. 27 to 35% D. 36 to 44%
xxTIMURxx [149]

Answer:

The correct answer would be B. 18 to 26%.

The muscle efficiency is calculated by dividing mechanical work output by total metabolic cost.

It is estimated that human muscles have an efficiency of about 18% to 26%.

The efficiency is low because most of the energy is lost when food energy is converted into ATP (adenosine triphophate).

In addition, there is second energy loss when energy in the form of ATP is converted into the mechanical energy such as rowing, cycling et cetera.

3 0
2 years ago
Read 2 more answers
A rocket moves upward, starting from rest with an acceleration of +29.4 for 3.98 s. it runs out of fuel at the end of the 3.98 s
topjm [15]
U = 0, initial upward speed
a = 29.4 m/s², acceleration up to 3.98 s
a = -9.8 m/s², acceleration after 3.98s

Let h₁ =  the height at time t, for t ≤ 3.98 s
Let h₂ =  the height at time t > 3.98 s

Motion for  t ≤ 3.98 s:
h₁ = (1/2)*(29.4 m/s²)*(3.98 s)² = 232.854 m
Calculate the upward velocity at t = 3.98 s
v₁ = (29.4 m/s²)*(3.98 s) = 117.012 m/s

Motion for t  > 3.98 s
At maximum height, the upward velocity is zero.
Calculate the extra distance traveled before the velocity is zero.
(117.012 m/s)² + 2*(-9.8 m/s²)*(h₂ m) = 0
h₂ = 698.562 m

The total height is
h₁ + h₂ = 232.854 + 698.562 = 931.416 m

Answer: 931.4 m (nearest tenth)

6 0
2 years ago
Read 2 more answers
A mass of 630g is hung on a spring. Using Force = mass x gravity, what is the force of the mass, acting on the spring?
hodyreva [135]

Answer:

6.174N or roughly 6.2N

Explanation:

630g=0.63kg

F=m*g=0.63*9.8=6.174N

3 0
1 year ago
Any ferrous metal object within or near the mri magnet has the potential of becoming a projectile. this is commonly referred to
PtichkaEL [24]
This phenomena is referred to as metal projectile injury/effect. MRI stands for magnetic resonance imaging. As expected, your body is subjected to a magnetic field. This is a technique to look inside your body without cutting it open. Metals should not be placed anywhere near an MRI because it will cause the metals to follow the direction of the magnetic field. 
4 0
2 years ago
A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init
Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

h=\frac{gt^2}{2}

For second stone

h=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}---2

Equating 1 &2 we get

\frac{gt^2}{2}=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}

\frac{g}{2}\left ( t-t+2.7\right )\left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

13.23\times \left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

26.46t-35.721-52.92t+142.884=0

t=4.05 s

4 0
2 years ago
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