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PolarNik [594]
2 years ago
11

Quickly spinning the handle of a hand generator, Kristina is able to light three bulbs in a circuit. When she spins the generato

r slowly, the bulbs are very dim. Which statement best explains why the slow generator is not able to power all three light bulbs?
Physics
1 answer:
erastova [34]2 years ago
5 0

Answer:

  • <u><em>Voltage is too low</em></u>

Explanation:

<em>Generators</em> produce a potential difference (voltage) by <em>spinning </em>a coil of wire in a magnetic field by induction.

The  produced voltage is proportional to the relative speed of the coil wire with respect to the magnetic field.

Hence, for a given generator, the higher the speed the higher the potential difference.

Therefore, it is concluded immediately that when Kristina spins the generator slowly, less potential difference (voltage) is generated.

Also, you must know that the brightness of the bulbs varies with the current: the higher the current, the brigther the bulbs.

On the other hand, the basic realtion between voltage (V), resistance (R), and current I) is given by Ohm's law: V = R × I. This is, voltage and current are proportional.

Since the generator is producting less voltage, for the same bulbs (which are resistors) , the current will be lower too. And, as stated, lower current means lower brightness, which explains why when Kristina spins the generator slowly, the bulbs are very dim.

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Answer:

Explanation:

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From the given  question, we are to determine the direction of the magnetic field bnet at a point A.

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\bar{B_{net}} = \bar{B_1} + \bar{B_2}

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\bar{B_{net}} = \frac{2 \mu_oI}{2 \pi r } \bar {k} \ out

Thus; \bar{B_{net}} points out of the screen at A.

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1 year ago
What is the force on a .8 kg peach falling freely in a Yakima orchard
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Aliun [14]

kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case =  4 m/s

when m = 0.125 kg

KE = (0.5) m v² =  (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg

KE = (0.5) m v² =  (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg

KE = (0.5) m v² =  (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg

KE = (0.5) m v² =  (0.5) (0.500) (4)² = 4 J

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When driving in heavy rain, or on a flooded road, your tires can ride on a thin film of water like skis;
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2 years ago
1. A liquid of mass 250g is heated with an electric heater. Its temperature rises from 30°C to 80°C, the specific heat capacity
statuscvo [17]

Answer:

1) 50 seconds 2) 100°C

Explanation:

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