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PolarNik [594]
2 years ago
11

Quickly spinning the handle of a hand generator, Kristina is able to light three bulbs in a circuit. When she spins the generato

r slowly, the bulbs are very dim. Which statement best explains why the slow generator is not able to power all three light bulbs?
Physics
1 answer:
erastova [34]2 years ago
5 0

Answer:

  • <u><em>Voltage is too low</em></u>

Explanation:

<em>Generators</em> produce a potential difference (voltage) by <em>spinning </em>a coil of wire in a magnetic field by induction.

The  produced voltage is proportional to the relative speed of the coil wire with respect to the magnetic field.

Hence, for a given generator, the higher the speed the higher the potential difference.

Therefore, it is concluded immediately that when Kristina spins the generator slowly, less potential difference (voltage) is generated.

Also, you must know that the brightness of the bulbs varies with the current: the higher the current, the brigther the bulbs.

On the other hand, the basic realtion between voltage (V), resistance (R), and current I) is given by Ohm's law: V = R × I. This is, voltage and current are proportional.

Since the generator is producting less voltage, for the same bulbs (which are resistors) , the current will be lower too. And, as stated, lower current means lower brightness, which explains why when Kristina spins the generator slowly, the bulbs are very dim.

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A vibrating standing wave on a string radiates a sound wave with intensity proportional to the square of the standing-wave ampli
uysha [10]

Answer:

string's damping is 1.03676

Explanation:

given data

sound level = 9.0 dB

time = 1 sec

to find out

string's damping

solution

we will apply here formula for string damping (b) that is

A(t) = A × e^{-bt}   ...................1

we know here I  ∝ A² so

√I(t) = √I × e^{-bt}  

√I(t) / √I =  e^{-bt}     .....................2

we know sound level decreases 9 dB i.e ΔdB = 9

so we can write

ΔdB = 10 log ( I(t) / I)

9 = 10 log ( I(t) / I)

I(t) / I = 10^{-0.9}

I(t) / I = 0.1258

and

√I(t) / I) = √0.1258 = 0.3546     .......................3

from equation 2 and 3 we get

0.3546 = e^{-bt}

take ln both side

-bt = ln 0.3546

here we know t is 1 sec

so

- b = - 1.03676

b = 1.03676

so here string's damping is 1.03676

8 0
2 years ago
A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the spee
dimulka [17.4K]
We can take as positive direction the direction of the train, and as negative direction the direction of the girl. The speed of the train relative to the girl will be given by the difference between the two velocities:
v' = v_t - v_g
which means
v'=75 m/s - (-10 m/s)=85 m/s
5 0
2 years ago
Read 2 more answers
Karyotypes are done by matching up _____________________________ so that they are paired up. Question 11 options:
Rufina [12.5K]

Homologous Chromosomes

6 0
2 years ago
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A pilot in a small plane encounters shifting winds. He flies 26.0 km northeast, then 45.0 km due north. From this point, he flie
cluponka [151]

Answer:

a) v₃ = 19.54 km, b)  70.2º north-west

Explanation:

This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition

vector 1 moves 26 km northeast

let's use trigonometry to find its components

         cos 45 = x₁ / V₁

         sin 45 = y₁ / V₁

         x₁ = v₁ cos 45

         y₁ = v₁ sin 45

         x₁ = 26 cos 45

         y₁ = 26 sin 45

         x₁ = 18.38 km

         y₁ = 18.38 km

Vector 2 moves 45 km north

        y₂ = 45 km

Unknown 3 vector

          x3 =?

          y3 =?

Vector Resulting 70 km north of the starting point

           R_y = 70 km

we make the sum on each axis

X axis

      Rₓ = x₁ + x₃

       x₃ = Rₓ -x₁

       x₃ = 0 - 18.38

       x₃ = -18.38 km

Y Axis

      R_y = y₁ + y₂ + y₃

       y₃ = R_y - y₁ -y₂

       y₃ = 70 -18.38 - 45

       y₃ = 6.62 km

the vector of the third leg of the journey is

         v₃ = (-18.38 i ^ +6.62 j^ ) km

let's use the Pythagorean theorem to find the length

         v₃ = √ (18.38² + 6.62²)

         v₃ = 19.54 km

to find the angle let's use trigonometry

           tan θ = y₃ / x₃

           θ = tan⁻¹ (y₃ / x₃)

           θ = tan⁻¹ (6.62 / (- 18.38))

           θ = -19.8º

with respect to the x axis, if we measure this angle from the positive side of the x axis it is

          θ’= 180 -19.8

          θ’= 160.19º

I mean the address is

          θ’’ = 90-19.8

          θ = 70.2º

70.2º north-west

3 0
2 years ago
The intensity at a distance of 6.0 m from a source that is radiating equally in all directions is 6.0 × 10-10 w/m2 . what is the
satela [25.4K]
The intensity is defined as the ratio between the power emitted by the source and the area through which the power is calculated:
I= \frac{P}{A} (1)
where
P is the power
A is the area

In our problem, the intensity is I=6.0 \cdot 10^{-10} W/m^2. At a distance of r=6.0 m from the source, the area intercepted by the radiation (which propagates in all directions) is equal to the area of a sphere of radius r, so:
A=4 \pi r^2 = 4 \pi (6.0 m)^2 = 452.2 m^2

And so if we re-arrange (1) we find the power emitted by the source:
P=IA = (6.0 \cdot 10^{-10}W/m^2)(452.2 m^2)=2.7 \cdot 10^{-7} W
3 0
2 years ago
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