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PolarNik [594]
2 years ago
11

Quickly spinning the handle of a hand generator, Kristina is able to light three bulbs in a circuit. When she spins the generato

r slowly, the bulbs are very dim. Which statement best explains why the slow generator is not able to power all three light bulbs?
Physics
1 answer:
erastova [34]2 years ago
5 0

Answer:

  • <u><em>Voltage is too low</em></u>

Explanation:

<em>Generators</em> produce a potential difference (voltage) by <em>spinning </em>a coil of wire in a magnetic field by induction.

The  produced voltage is proportional to the relative speed of the coil wire with respect to the magnetic field.

Hence, for a given generator, the higher the speed the higher the potential difference.

Therefore, it is concluded immediately that when Kristina spins the generator slowly, less potential difference (voltage) is generated.

Also, you must know that the brightness of the bulbs varies with the current: the higher the current, the brigther the bulbs.

On the other hand, the basic realtion between voltage (V), resistance (R), and current I) is given by Ohm's law: V = R × I. This is, voltage and current are proportional.

Since the generator is producting less voltage, for the same bulbs (which are resistors) , the current will be lower too. And, as stated, lower current means lower brightness, which explains why when Kristina spins the generator slowly, the bulbs are very dim.

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An object is located 25.0 cm from a convex mirror. The image distance is -50.0 cm. What is the magnification?
Lynna [10]

Answer:

\boxed{\sf Magnification \ (m) = 2}

Given:

Object distance (u) = 25.0 cm

Image distance (v) = -50.0 cm

To Find:

Magnification (m)

Explanation:

\boxed{\bold{\sf Magnification  \: (m) = - \frac{Image  \: distance  \: (v)}{Object  \: distance  \: (u)}}}

Substituting values of Image distance(v) & Object distance (u) in the equation:

\sf \implies m =  -  \frac{( - 50)}{25}

-(-50) = 50:

\sf \implies m =  \frac{50}{25}

\sf \implies m =  \frac{2 \times  \cancel{25}}{ \cancel{25}}

\sf \implies m = 2

4 0
2 years ago
What is a manifest function of a married father joining the military
katovenus [111]

Answer:

Explanation:

Manifest- he supports his family, fights for a living. He will support his family while he fights for a living it is basically his job. By fighting in war that is what income his family will get

6 0
2 years ago
Read 2 more answers
A 2600-m-high mountain is located on the equator. how much faster does a climber on top of the mountain move than a surfer at a
puteri [66]

The climber move 0.19 m/s  faster than surfer on the nearby beach.

Since both the person are on the earth, and moves with the constant angular velocity of earth, however there linear velocity is different.

Number of seconds in a day, t=24*60*60=86400 sec

The linear speed on the beach is calculated as

V1=\frac{2πr}{t}

Here, t is the time

Plugging the values in the above equation

V1=\frac{2π*6.4*10^6}{86400}=465.421 m/s

Velocity on the mountain is calculated as

V2=\frac{2π(r+h)}{t}

Plugging the values in the above equation

V2=\frac{2π(6.4*10^6+2600}{86400}=465.61 m/s

Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s

5 0
2 years ago
An electron starts from rest 3.00 cm from the center of a uniformly charged sphere of radius 2.00 cm. if the sphere carries a to
Sidana [21]
Answer:
velocity = 7.26 * 10^6 m/sec

Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity

Hope this helps :)

7 0
2 years ago
A person in a boat sees a fish in the water (n = 1.33, the light rays making an angle of 40? relative to the water's surface. wh
jek_recluse [69]
We know that the measure of an incident ray is:  α 1 = 40°.
The index of refraction:
- for the air : n 1 = 1.00,
- for the water: n 2 = 1.33
Snell`s Law of Refraction :
n 1 · sin α 1 = n 2 · sin α 2
sin α 2 = n 1 · sin α 1 / n 2 =
= 1.00 · sin 40° / 1.33 = 0.64278 / 1.33 = 0.4833
α 2 = sin ^(-1) 0.4833
α 2 = 28.9 °
Answer: The angle relative to the water`s surface of the rays when beneath the surface is 28.9°.

4 0
2 years ago
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