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Murljashka [212]
2 years ago
11

Winston earns $140.00 by selling 56 hot dogs at a concession stand at school. Using the same rate for the cost of one hot dog, h

ow many more hot dogs would Winston need to sell to earn a total of $175.00
Mathematics
1 answer:
Natalka [10]2 years ago
6 0

Answer:

Number of hot dogs = 14

Step-by-step explanation:

Winston earns $140.00 by selling 56 hot dogs at a concession stand at school.

We have to find how many more hot dogs he would be able to sell if we assume the same price as before for each hot dog.

Let the price of 1 hot dog = $x

Writing the equation,

140 = 56\times x

x = \frac{140}{56}

x = $2.50

He has to earn $175.00 so we need to find how many more hot dogs he has to sell.

He needs to earn $35 more.

Number of hot dogs = \frac{35}{2.5} = 14 hot dogs.

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What number is represented by 4x²+17x+2 if x=10?
Fynjy0 [20]

Answer:

at x = 10,   4x^{2}  + 17x + 2  = 572

Step-by-step explanation:

The given equation is 4x^{2}  + 17x + 2

Here, lets substitute the value of x = 10

So, the equation simplifies to ,

4 \times (10)^{2}  + 17(10) + 2

= (4 x 100)  + 170 + 2 = 400 + 170 + 2

= 572

So, at x = 10,   4x^{2}  + 17x + 2 = 572

4 0
2 years ago
Write the rational number as a decimal. −18/5
Angelina_Jolie [31]

Answer:

-3.6

Step-by-step explanation:

When plugged into a calculator, the answer turns out to be -3.6, which is a decimal.

6 0
2 years ago
Read 2 more answers
Circle C is shown. Secants U W and Y W intersect at point W outside of the circle. Secant U W intersect the circle at point V an
Nookie1986 [14]
78 degrees mArc V X in the diagram
4 0
2 years ago
Triangle MNO is an equilateral triangle with sides measuring 16 StartRoot 3 EndRoot units. Triangle M N O is an equilateral tria
Lesechka [4]

Answer:

The correct option is second one i.e 24 units.

Therefore the height of the triangle is

NR=24\ units

Step-by-step explanation:

Given:

An equilateral triangle has all sides equal.

ΔMNO is an Equilateral Triangle with sides measuring,

NM = MO = ON =16\sqrt{3}

NR is perpendicular bisector to MO such that

MR=RO=\dfrac{MO}{2}=\dfrac{16\sqrt{3}}{2}=8\sqrt{3} .NR ⊥ Bisector.

To Find:

Height of the triangle = NR = ?

Solution :

Now we have a right angled triangle NRM at ∠R =90°,

So by applying Pythagoras theorem we get

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting the values we get

(MN)^{2} = (MR)^{2}+(NR)^{2}\\\\(16\sqrt{3})^{2}=(8\sqrt{3})^{2}+(NR)^{2}\\\\(NR)^{2}=768-192=576\\Square\ rooting\ we\ get\\NR=\sqrt{576}=24\ units

Therefore the height of the triangle is

NR=24\ units

6 0
2 years ago
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O is the centre of the circle and ABC and EDC are tangents to the circle. Find the size of angle BCD. You must give reasons in y
Simora [160]

Answer:

mBCD = 28°

Step-by-step explanation:

The angle mBFD inscribes the arc mBD, so we have that:

mBFD = mBD/2

76 = mBD/2

mBD = 152°

The angle mBOD is a central angle related to the arc mBD, so we have that:

mBOD = mBD = 152°

In the quadrilateral BODC, the sum of internal angles needs to be equal to 360° (property of all convex quadrilaterals). The angles mCBO and mCDO are right angles, because EDC and ABC are tangents to the circle.

So, we have that:

mBOD + mCDO + mBCD + mCBO = 360

152 + 90 + mBCD + 90 = 360

mBCD = 360 - 90 - 90 - 152

mBCD = 28°

7 0
2 years ago
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