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goldenfox [79]
2 years ago
3

Air bags in cars operate according to the reaction below. How many grams of nitrogen gas are produced during the decomposition o

f 3.25 g Na3N?
Chemistry
1 answer:
Serjik [45]2 years ago
5 0

Answer : The mass of nitrogen gas produced during the decomposition of Na_3N are, 0.546 grams.

Solution : Given,

Mass of Na_3N = 3.25 g

Molar mass of Na_3N = 83 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate the moles of Na_3N.

\text{ Moles of }Na_3N=\frac{\text{ Mass of }Na_3N}{\text{ Molar mass of }Na_3N}=\frac{3.25g}{83g/mole}=0.039moles

Now we have to calculate the moles of MgO

The balanced chemical reaction will be,

2Na_3N\rightarrow N_2+6Na

From the balanced reaction we conclude that

As, 2 mole of Na_3N react to give 1 mole of N_2

So, 0.039 moles of Na_3N react to give \frac{0.039}{2}=0.0195 moles of N_2

Now we have to calculate the mass of N_2

\text{ Mass of }N_2=\text{ Moles of }N_2\times \text{ Molar mass of }N_2

\text{ Mass of }N_2=(0.0195moles)\times (28g/mole)=0.546g

Therefore, the mass of nitrogen gas produced during the decomposition of Na_3N are, 0.546 grams.

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eduard

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15                                    

for CH3 COOH, pKa = 4.74    

Explanation:

The concentration of the solution given is 0.1 M has a pH closest to 7

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for buffers( acidic)                                               pH = pKa + log [salt] / [acid]

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for CH3 COOH, pKa = 4.74                

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2 years ago
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The mass number goes on top, and the atomic number goes on bottom. 
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