Question

How many grams are there in 7.5 X10^23 molecules of H2SO4?

Answer 1

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

 7.5 X10^23 molecules of H2SO4 ( 1 mol / 6.022x10^23 molecules ) (98.08 g / 1 mol ) = 122.15 grams H2SO4

Answer 2

Answer : The mass of $H_2SO_4$ are, 117.6 grams.

Explanation :

First we have to calculate the moles of $H_2SO_4$.

As, $6.022\times 10^{23}$ molecules of $H_2SO_4$ present in 1 mole of $H_2SO_4$

So, $7.5\times 10^{23}$ molecules of $H_2SO_4$ present in $\frac{7.5\times 10^{23}}{6.022\times 10^{23}}=1.2$ mole of $H_2SO_4$

Now we have to calculate the mass of $H_2SO_4$.

$\text{Mass of }H_2SO_4=\text{Moles of }H_2SO_4\times \text{Molar mass of }H_2SO_4$

Molar mass of $H_2SO_4$ = 98 g/mole

$\text{Mass of }H_2SO_4=1.2mole\times 98g/mole=117.6g$

Therefore, the mass of $H_2SO_4$ are 117.6 grams.