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AleksandrR [38]
2 years ago
13

The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social me

dia. The distribution of time on social media is known to be Normal. The proportion of students spending at least 2 hours on social media equals:
Mathematics
1 answer:
Rashid [163]2 years ago
4 0

Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .

Step-by-step explanation:

Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.

The distribution of time on social media is known to be Normal.

Let x be the number of minutes spent on social media.

Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

P(x\geq120)=1-P(x

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .

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Taya2010 [7]
2 1/3 cups of sugar

5 3/4 - 2 1/2
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1 year ago
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Neporo4naja [7]
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2 years ago
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Annette [7]

Answer:

error in step 1

Step-by-step explanation:

well where is does the step not make sense?

remember cos(pi) = -1 and sin(pi)=0

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6 0
1 year ago
Read 2 more answers
Katrina has the option of an 8-year non-subsidized student loan of $32,000 at an annual interest rate of 3.5% or an 8-year subsi
Fiesta28 [93]

Answer: katrina will pay less interest on the 8-year non subsidized student loan

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The total interest paid on the subsidized loan is USD 11,520

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Divide 169 mi in the ratio 5 : 8.
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