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AleksandrR [38]
2 years ago
13

The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social me

dia. The distribution of time on social media is known to be Normal. The proportion of students spending at least 2 hours on social media equals:
Mathematics
1 answer:
Rashid [163]2 years ago
4 0

Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .

Step-by-step explanation:

Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.

The distribution of time on social media is known to be Normal.

Let x be the number of minutes spent on social media.

Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

P(x\geq120)=1-P(x

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .

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Steve stayed after school for extra activities 55% of the 180 school days this year. How many days did Steve stay after school?
musickatia [10]

Answer:

11/20 or 99/180 days

Step-by-step explanation:

55/100 converted to ?/180

180/100=1.8

so you would do the same on the numerator which is 55*1.8=99

99/180= 33/60=11/20

7 0
1 year ago
Complete the missing parts of the paragraph proof. Draw a perpendicular from P to AB. Label the intersection C. We are given tha
zvonat [6]
<span>1) We are given that PA = PB, so PA ≅ PB by the definition of the radius.

</span>When you draw a perpendicular to a segment AB, you take the compass, point it at A and draw an arc of size AB, then you do the same pointing the compass on B. Point P will be one of the intersections of those two arcs. Therefore PA and PB correspond to the radii of the arcs, which were taken both equal to AB, therefore they are congruent. 
 
2) We know that angles PCA and PCB are right angles by the definition of perpendicular.

Perpendicularity is the relation between two lines that meet at a right angle. Since we know that PC is perpendicular to AB by construction, ∠PCA and ∠PCB are right angles.
 
3) PC ≅ PC by the reflexive property congruence.

The reflexive property congruence states that any shape is congruent to itself.

4) So, triangle ACP is congruent to triangle BCP by HL, and AC ≅ BC by CPCTC (corresponding parts of congruent triangles are congruent). 

CPCTC states that if two triangles are congruent, then all of the corresponding sides and angles are congruent. Since ΔACP ≡ ΔBCP, then the corresponding sides AC and BC are congruent.
 
5) Since PC is perpendicular to and bisects AB, P is on the perpendicular bisector of AB by the definition of the perpendicular bisector. 

<span>The perpendicular bisector of a segment is a line that cuts the segment into two equal parts (bisector) and that forms with the segment a right angle (perpendicular). Any point on the perpendicular bisector has the same distance from the segment's extremities. PC has exactly the characteristics of a perpendicular bisector of AB. </span>
6 0
1 year ago
Read 2 more answers
The equation of the blue line is y = –x + 5. Manipulate the orange line by setting the sliders so its slope, m, is –1 and its y-
denis23 [38]

Okay, so the lines are the same, so the answer would be the last question.

m is another word for slope, and the slopes are both -1.

the y-intercepts are also both 5.

I can't see whatever graph is on the problem, but I am pretty sure this would be the answer.

I hope this helps.

7 0
1 year ago
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Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm
Andreyy89
Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
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a(9) - a(4) => 5d = 35
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a(2) = a + d = 34 + 7 = 41.

4 0
2 years ago
Build 7 identical towers with a box of 546 blocks. How many blocks are there in each tower?
kvv77 [185]

Answer:

78

Step-by-step explanation:

546 ÷ 7 = 78. So their is 78 blocks in each tower.

5 0
1 year ago
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