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AleksandrR [38]
2 years ago
13

The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social me

dia. The distribution of time on social media is known to be Normal. The proportion of students spending at least 2 hours on social media equals:
Mathematics
1 answer:
Rashid [163]2 years ago
4 0

Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .

Step-by-step explanation:

Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.

The distribution of time on social media is known to be Normal.

Let x be the number of minutes spent on social media.

Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

P(x\geq120)=1-P(x

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .

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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
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Answer: In the beginning he was given 27 sweets.

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2 years ago
In △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP . Find the area of △ABC if the area of △BMP
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