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Vinil7 [7]
2 years ago
12

The volume of the sphere is StartFraction 500 Over 3 EndFractionπ cubic units. A sphere has a radius of x units. What is the val

ue of x? 4 units 5 units 8 units 10 units
Mathematics
2 answers:
Tpy6a [65]2 years ago
4 0

Answer:

(b) Radius of the sphere = 5 units.

Step-by-step explanation:

Here, given:

The volume of the sphere  = (\frac{500}{3})\pi cubic units  ... (1)

Also, radius of the sphere  = x  units

Now, VOLUME OF SPHERE  = (\frac{4}{3}) \pi r^3

So, volume of a sphere with radius x  = (\frac{4}{3}) \pi (x)^3

But volume of sphere is given by (1).

\implies (\frac{500}{3})\pi = (\frac{4}{3}) \pi (x)^3\\\implies (\frac{500}{3}) = (\frac{4}{3}) (x)^3\\\implies x^3 = (\frac{500}{3})  \times (\frac{3}{4})  = 125\\\implies x^ 3 = 125 = (5)^3\\\implies x  = 5

Hence, radius of the sphere = 5 units.

FrozenT [24]2 years ago
4 0

Answer:

5 units

Step-by-step explanation:

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katen-ka-za [31]

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Step-by-step explanation:

1200/3z = 8

400=8/3 year for each building

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2/3 times 25 is 16.666

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1 year ago
What is the value of x which proves that the runways are parallel? What is the measure of the larger angle?
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2 years ago
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The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22
NISA [10]

Answer:

a) v(2\,s) = 2.9\,\frac{m}{s}, b) v(4\,s) = -16.7\,\frac{m}{s}, c) t = 2.296\,s, d) h (2.296\,s) = 27.829\,m, e) t \approx 4.679\,s, f) v(4.679\,s) = -23.354\,\frac{m}{s}

Step-by-step explanation:

The velocity function can be derived by the differentiating the height function:

v = 22.5-9.8\cdot t

Velocities after 2 and 4 seconds are, respectively:

a) v(2\,s) = 2.9\,\frac{m}{s}

b) v(4\,s) = -16.7\,\frac{m}{s}

The maximum height is reached when velocity is zero. Then:

22.5-9.8\cdot t = 0

c) t = 2.296\,s

The maximum height is:

d) h (2.296\,s) = 27.829\,m

The time required to hit the ground is:

-4.9\cdot t^{2}+22.5\cdot t +2 = 0

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t_{1} \approx 4.679\,s

t_{2} \approx -0.087\,s

Only the first root is physically reasonable.

e) t \approx 4.679\,s

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7 0
1 year ago
PLSS HELPPP 20 POINTS
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Answer:

a

Step-by-step explanation:

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1 year ago
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The volumes of two similar figures are 343 mm3 and 512 mm3. If the surface area of the larger figure is 192 mm2, what is the sur
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In geometry, similar figures are those whose ratios of the  corresponding sides are equal and the corresponding  angles are congruent. In relation to the volume, we determine first the cube roots of the given and find the ratio as shown below.
 
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The value of x from the equation is 147 mm². 

The area therefore of the smaller figure is 147 mm².
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