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Vinil7 [7]
2 years ago
12

The volume of the sphere is StartFraction 500 Over 3 EndFractionπ cubic units. A sphere has a radius of x units. What is the val

ue of x? 4 units 5 units 8 units 10 units
Mathematics
2 answers:
Tpy6a [65]2 years ago
4 0

Answer:

(b) Radius of the sphere = 5 units.

Step-by-step explanation:

Here, given:

The volume of the sphere  = (\frac{500}{3})\pi cubic units  ... (1)

Also, radius of the sphere  = x  units

Now, VOLUME OF SPHERE  = (\frac{4}{3}) \pi r^3

So, volume of a sphere with radius x  = (\frac{4}{3}) \pi (x)^3

But volume of sphere is given by (1).

\implies (\frac{500}{3})\pi = (\frac{4}{3}) \pi (x)^3\\\implies (\frac{500}{3}) = (\frac{4}{3}) (x)^3\\\implies x^3 = (\frac{500}{3})  \times (\frac{3}{4})  = 125\\\implies x^ 3 = 125 = (5)^3\\\implies x  = 5

Hence, radius of the sphere = 5 units.

FrozenT [24]2 years ago
4 0

Answer:

5 units

Step-by-step explanation:

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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
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Vladimir [108]

Answer:

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Step-by-step explanation:

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  1                    18               3.44

  2                    55              10.50

  3                    81               15.46

  4                    109             20.80

  5                     88              16.79

  6                     66              12.60

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  8                     17                3.24

  9                     17                3.24

  10                   19                3.63

   15                  15                2.86

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P(Y \leq 4) = 0.0344 + 0.1050 + 0.1546 + 0.2080 = 0.502

We convert the percent into probabilities by dividing them with 100. This gave us the required probabilities.

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2 years ago
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