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Advocard [28]
1 year ago
9

The power 3 Superscript negative 3 equals StartFraction 1 Over 27 EndFraction . Which expression is equivalent to 3 Superscript

negative 3?
StartFraction 1 Over 3 squared EndFraction
StartFraction 1 Over 3 cubed EndFraction
StartFraction 1 Over 9 cubed EndFraction
StartFraction 1 Over 3 Superscript 9 EndFraction
Mathematics
2 answers:
LiRa [457]1 year ago
8 0

Answer:

B.  \frac{1}{3^3}

Step-by-step explanation:

We have been given an expression 3^{-3}=\frac{1}{27}. We are asked to find an equivalent expression to 3^{-3}.

We will use exponent properties to solve our given problem.

We will use exponent property a^{-b}=\frac{1}{a^b}  to rewrite our given expression.

Upon comparing our expression with exponent property, we can see that a=3 and -b=-3.

3^{-3}=\frac{1}{3^3}

Therefore, expression \frac{1}{3^3} in equivalent to  3^{-3} and option B is the correct choice.

SpyIntel [72]1 year ago
4 0

Answer:

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.   23

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given that at  a large high school 40 percent of the students walk to school, 32 percent of the students have been late to school at least once, and 37.5 percent of the students who walk to school have been late to school at least once.

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Hello There!

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