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Leya [2.2K]
2 years ago
14

Paul can install a 300-square-foot hardwood floor in 18 hours. Matt can install the same floor in 22 hours. How long would it ta

ke Paul and Matt to install the floor working together?A. 4 hoursB. 9.9 hoursC. 13.2 hoursD. 30 hours
Mathematics
1 answer:
Marrrta [24]2 years ago
3 0

Answer: B. 9.9 hours

Step-by-step explanation:

Given : Paul can install a 300-square-foot hardwood floor in 18 hours.

We consider whole job as 1.

Rate of work per hour for Paul = r_1=\dfrac{1}{18}

Matt can install the same floor in 22 hours.

Rate of work per hour for Matt = r_2=\dfrac{1}{22}

Now , when they both work together , the rate of work = r=\dfrac{1}{t} , where t is time taken by both together.

Since , r=r_1+r_2

\dfrac{1}{t}=\dfrac{1}{18}+\dfrac{1}{22}

\dfrac{1}{t}=\dfrac{11+9}{198}=\dfrac{20}{198}=\dfrac{10}{99}\\\\\Rightarrow\ t=\dfrac{99}{10}=9.9

Hence, it would take 9.9 hours to install the floor working together.

Therefore , the correct answer is  B. 9.9 hours .

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For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

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For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

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