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mr Goodwill [35]
2 years ago
5

A ball collides elastically with an immovable wall fixed to the earth’s surface. Which statement is false? 1. The ball's speed i

s unchanged by the collision.2. The ball does no net work on the wall.3. The ball's kinetic energy is unchanged by the collision.4. the wall doos no net work on the ball.5. the ball's size and shape are unchanged by the collision.6. All of these statements are true7. The ball's momentum is unchanged by the collision
Physics
1 answer:
aleksley [76]2 years ago
4 0

Answer:

Statements 4, 6 & 7 are false.

Explanation:

For any elastic collision the vector sum of the total momentum of the system is zero.

Here we have an elastic collision between the ball and a fixed wall. The velocity of the ball will always remain zero whereas the velocity (hence momentum) of the ball will totally revert after the collision.

Initial momentum of the ball is given as:

p=m.v

where:

m = mass of the ball

v = initial velocity of the body

after the elastic collision:

p=m.(-v)

  • Here the direction of the velocity is reversed, hence the momentum is changed only in terms of direction violates the statement 7.
  • At the moment of collision the ball and the wall exert an equal and opposite force mutually on each other. The wall does not moves in any case whereas the ball moves in the direction of the reaction force of the wall hence it does some work on the ball violating the statement 4.
  • Since the collision is elastic the shape and size of the ball remains intact.
  • From the above explanation it is clear that that not all the given statements are correct hence statement 6 goes violated.
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A passenger compartment of a rotating amusement park ride contains a bench on which a book of mass
Basile [38]

a) 120 s

b) v = 0.052R [m/s]

Explanation:

a)

The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).

The graph of the problem is missing, find it in attachment.

To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.

The first point we take is t = 0, when the position of the book is x = 0.

Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.

Therefore, the period is

T = 120 s - 0 s = 120 s

b)

The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.

The perimeter of the wheel is:

L=2\pi R

where R is the radius of the wheel.

The period of revolution is:

T=120 s

Therefore, the tangential speed of the book is:

v=\frac{L}{T}=\frac{2\pi R}{120}=0.052R

8 0
2 years ago
(Another tomato/skyscraper problem.) You are looking out your window in a skyscraper, and again your window is at a height of 45
Ivan

Answer:

1027.2 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.2 ft/s

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{450-\frac{1}{2}\times 32.2\times 2^2}{2}\\\Rightarrow u=192.8\ ft/s

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{192.8^2-0^2}{2\times 32.2}\\\Rightarrow s=577.20\ m

The height the tomato would fall is 450+577.2 = 1027.2 m

6 0
2 years ago
A 1500 kg car traveling at 20 m/s suddenly runs out of gas while approaching the valley shown in the figure. The alert driver im
geniusboy [140]

Answer:

v_f = 17.4 m / s

Explanation:

For this exercise we can use conservation of energy

starting point. On the hill when running out of gas

          Em₀ = K + U = ½ m v₀² + m g y₁

final point. Arriving at the gas station

         Em_f = K + U = ½ m v_f ² + m g y₂

energy is conserved

         Em₀ = Em_f

         ½ m v₀ ² + m g y₁ = ½ m v_f ² + m g y₂

        v_f ² = v₀² + 2g (y₁ -y₂)

         

we calculate

        v_f ² = 20² + 2 9.8  (10 -15)

        v_f = √302

         v_f = 17.4 m / s

8 0
2 years ago
A batter swings at a baseball. The action force is the bat hitting the ball with a force of 5N. What is the reaction force?
omeli [17]
The ball hitting the bat
6 0
2 years ago
Read 2 more answers
an elastic cord 61 cm long when a weight of 75N hangs from it, but 85cm when a weight of 210N hangs from it. what is the spring
pishuonlain [190]

Answer:

560 N/m

Explanation:

F = kx

75 N = k (0.61 m − L)

210 N = k (0.85 m − L)

Divide the equations:

2.8 = (0.85 − L) / (0.61 − L)

2.8 (0.61 − L) = 0.85 − L

1.708 − 2.8L = 0.85 − L

0.858 = 1.8L

L = 0.477

Plug into either equation and find k.

75 = k (0.61 − 0.477)

k = 562.5

Rounded to two significant figures, k = 560 N/m.

3 0
1 year ago
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