<u>Answer</u>
672,000 Joules
<u>Explanation</u>
Gravitational potential energy (P.E) is the energy possessed by a body that is at a potential height from the ground.
IT is calculated by the formula;
P.E = mgh
Where m ⇒ mass
g ⇒ acceleration due to gravity
h ⇒ height from trhe ground.
P.E = 1200 × 1.6 × 350
= 672,000 Joules.
To solve this problem it is necessary to apply the concepts related to the magnetic dipole moment in terms of the current and the surface area, as well as the current density, as a function of the current over the area.
Part A) By definition we know that magnetic dipole moment is

Where,
I = Current
S = Area

Replacing with our values we have that,

Re-arrange to find I,

Part B) To find the Current density we need to find the cross sectional area of the Wire:

Finally the current density is simply J

PART C) Finally to make the comparison with the given values we have to cross-sectional area would be

Therefore the current density would be

Comparing the two values we can see that the 2mm wire has a higher current density.
Explanation:
Upstroke is a mechanism which helps to raise the plunger and downstroke helps to help lower the plunger. On the up-stroke of the plunger, the lower valve opens and the upper valve is closed. ... Whereas, on the downstroke, the lower valve closes and the upper one opens.
Answer:
The density of the mercury is 13.2 g/cm³
Explanation:
Density is a measurement that compares the amount of matter an object
has to its volume
Density is equal to mass divided by volume
We need to find the density of mercury if 500 cm³ has a mass of
6.60 kg in g/cm
We must to change The kilogram to grams
The mass of mercury is 6.60 kilograms
1 kilogram = 1000 grams
6.60 kilograms = 6.60 × 1000 = 6600 grams
Density = mass ÷ volume
The volume of the mercury is 500 cm³
The density = 6600 ÷ 500
The density = 13.2 g/cm³
<em>The density of the mercury is 13.2 g/cm³ </em>
Answer:

Explanation:
The fusion reaction in this problem is

The total energy released in the fusion reaction is given by

where
is the speed of light
is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products
For this fusion reaction we have:
is the mass of one nucleus of hydrogen
is the mass of one nucleus of helium
So the mass defect is:

The conversion factor between atomic mass units and kilograms is

So the mass defect is

And so, the energy released is:
