Answer:
The change in the centripetal acceleration of the brother,
Δa = V₂²/R - V₁²/R
Explanation:
Given data,
A sister spins her brother in a circle of radius, R
The angular velocity of the brother, ω₁ = V₁/R
The angular velocity of the brother, ω₂ = V₂/R
The centripetal acceleration is given by the relation
a = V²/R
Therefore change in the centripetal acceleration of the brother,
Δa = V₂²/R - V₁²/R
Answer:u=97.41m/s
Explanation:
Given
inclination 
Horizontal distance travel by Particle 
Vertical height 
Let u be the initial velocity
calculating vertical distance

-------1
Calculating horizontal distance


put value of t in equation 1





at 


If speed = distance/time , then time = speed/distance.
So...
Speed of light = 3*10^8(m/s)
Average distance from Earth to Sun = 149.6*10^9(m)
Therefore, t=(3*10^8(m/s))/(149.6*10^9(m))
I hope this was a helpful explanation, please reply if you have further questions about the problem.
Good luck!
Answer:
The magnitude of the acceleration of the box is 2 m/s².
Explanation:
Given:
Mass of the box,
kg
Force acting towards east,
N
Frictional force acting towards west,
N
Let the acceleration be
m/s².
Now, net force acting on the box towards east is given as:

From Newton's second law of motion,

Therefore, the magnitude of the acceleration of the box is 2 m/s².