Answer:
v = 2.21 m/s
Explanation:
The foreman had released the box from rest at a height of 0.25 m above the ground.
We need to find the speed of the crate when it reaches the bottom of the ramp. Let v is the velocity at the bottom of the ramp. It can be calculated using conservation of energy as follows :

So, its velocity at the bottom of the ramp is 2.21 m/s.
Answer:

Explanation:
The free body diagram of the block on the slide is shown in the below figure
Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces
N is the reaction force between the block and the slide
For equilibrium along x-axis we have

Using value of N from equation β in α we get value of force as

Applying values we get

Answer:
Explanation:
The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:
(1)
Where:
is the rock's final height
is the rock's initial height
is the rock's initial velocity
is the angle at which the rock was thrown (directly upwards)
is the time
is the acceleration due gravity in Planet X
Then, isolating
and taking into account
:
(2)
(3)
Finally:
(4) This is the acceleration due gravity in Planet X
Answer:
The airplane should release the parcel
m before reaching the island
Explanation:
The height of the plane is
, and its speed is v=150 m/s
When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is
[1]
And the distance X is
x = V.t [2]
Being t the time elapsed since the release of the parcel
If we isolate t from the equation [1] and replace it in equation [2] we get

Using the given values:

x =
m
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