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2 years ago

Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?

Chemistry

1 answer:

kap26 [50]2 years ago

6 0

Answer:

Empirical formula is C₇H₅F₃

Explanation:

Given data:

Percentage of hydrogen = 3.45%

Percentage of carbon = 57.54%

Percentage of fluorine = 39.01%

Empirical formula = ?

Solution:

Number of gram atoms of H = 3.45 / 1.01 = 3.42

Number of gram atoms of F = 39.01 / 18.99 = 2.05

Number of gram atoms of C = 57.54/ 12.01 = 4.79

Atomic ratio:

C : H : F

4.79/2.05 : 3.42/2.05 : 2.05/2.05

2.34 : 1.67 : 1

C : H : F = 3(2.34 : 1.67 : 1 )

Empirical formula is C₇H₅F₃.

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The French chemists, Pierre L. Dulong and Alexis T. Petit, noted in 1819 that the molar heat capacity of many solids at ordinary

natita [175]

The empirical formula of the compound : <u><em>RbO₂</em></u>

<h3>Further explanation</h3>

Dulong and Petit's rule's rule, which says that the molar heat capacity, Cp, of a solid can be expressed as

$\large{\boxed{\bold{Cp=N(3R)}}$

Where N is the number of atoms per formula unit and R is the universal gas constant

While the value of R is:

R = 8.3144621 J / K · mol

then:

3R = 24.94 J / K · mol

Heat capactiy per gram of a compound containing rubidium and oxygen is 0.64 J · K⁻¹ · g⁻¹

We try the possible empirical formula from the composition of Rb and O

Rb₂O

So the number of atoms: 3 (Rb = 2 atoms, O = 1 atom)

Then the value of the Cp:

Molar mass Rb₂O = 2.85.5 + 1.16 = 187 g/mol

$\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{187}\\\\0.64\neq0.4$

Then this empirical formula Rb₂O is not appropriate

RbO₂

So the number of atoms: 3 (Rb = 1 atom, O = 2 atoms)

Then the value of the Cp:

Molar mass RbO₂ = 1.85.5 + 2.16 = 117.5 g / mol

$\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{117.5}\\\\0.64=0.64$

Then this empirical formula RbO₂ is appropriate

<h3>Learn more </h3>

chemical bond

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electron dots

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Keywords: an empirical formula,compound, gas constant, Dulong and Petit's rule,the molar heat capacity

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7 0

2 years ago

PLS HELP ASAP, WILL GIVE 100 POINTS.

Ivan

Answer: values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

location of the electron: In the 7th energy level away from the nucleus.

Explanation:

From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.

The orbital designation of the describe electron is 7d

Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus.

Got it from quasarJose

Hope it helps

5 0

2 years ago

Which of the following is a correctly written chemical equation that demonstrates the conservation of mass?

Fantom [35]

Answer:

Option D is correct.

H₂O + CO₂ → H₂CO₃

Explanation:

First of all we will get to know what law of conservation of mass states.

According to this law, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Example:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

Now we will apply this law to given chemical equations:

A) H₂ + O₂ → H₂O

There are two hydrogen and two oxygen atoms present on left side while on right side only one oxygen and two hydrogen atoms are present so mass in not conserved. This equation not follow the law of conservation of mass.

B) Mg + HCl → H₂ + MgCl₂

In this equation one Mg, one H and one Cl atoms are present on left side while on right side two hydrogen, one Mg and two chlorine atoms are present. This equation also not follow the law of conservation of mass.

C) KClO₃ → KCl + O₂

There are one K, one Cl and three O atoms are present on left side of chemical equation while on right side one K one Cl and two oxygen atoms are present. This equation also not following the law of conservation of mass.

D) H₂O + CO₂ → H₂CO₃

There are two hydrogen, one carbon and three oxygen atoms are present on both side of equation thus, mass remain conserved. Thus is correct option.

6 0

2 years ago

An alpha particle has the same composition as a helium nucleus.<br><br> True<br> False

Schach [20]

Your answer would be True

3 0

2 years ago

Read 2 more answers

Moist to wet as warm is to:<br><br> Luke<br> Boiling or<br> Steamy

Vinvika [58]

Answer:steamy

Explanation:

8 0

2 years ago

Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?​

Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?