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kipiarov [429]
2 years ago
14

A stone is thrown horizontally from the top of a cliff and eventually hits the ground below. A second stone is dropped from rest

from the same cliff, falls through the same height, and also hits the ground below. Ignore air resistance. Discuss whether each of the following quantities is different or the same in the two cases; if there is a difference, describe the difference:_________ (a) displacement, (b) speed just before impact with the ground,(c) time of flight.
Physics
1 answer:
Rama09 [41]2 years ago
5 0

Answer:

a) Horizontally thrown stone has greater displacement.

b) Horizontally thrown stone has greater impact speed

c) Both have the same time of flight.

Explanation:

As both stones has the same vertical velocity so the time of flight is the same. If we talk about the displacement then the stone which is thrown horizontally has the horizontal displacement and vertical displacement too so it has greater net displacement in comparison with that of stone thrown vertically. From going top to bottom the kinetic energy changes into potential energy. So the change of energy is same for both cases but the one which thrown horizontally has the higher value of kinetic enrgy initially and also finally so it's impact speed is greater.

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Aleonysh [2.5K]

Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

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W = 980 kJ

The pump does 980 kJ of work.

3 0
2 years ago
Read 2 more answers
A machine part is vibrating along the x-axis in simple harmonic motion with a period of 0.27 s and a range (from the maximum in
Gnoma [55]

Answer:

x = -1.437 cm

Explanation:

The general equation for position of Simple harmonic motion is given as:

x = A sin(\omega t)          ........(1)

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A = Amplitude of the wave

ω = Angular velocity

t = time

In this case, the amplitude is just half the range,

thus,

A =\frac{3cm}{2}=1.5cm  (Given range = 3cm)

A = 1.5 cm  

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\omega=\frac{2\pi}{T}

Where, T = time period of the wave =0.27s (given)

\omega=\frac{2\pi}{0.27s}

or

\omega=23.27s^{-1}

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x = 1.5 sin(23.27\times 55)

on solving the above equation we get,

x = -1.437 cm

here the negative sign depicts the position in the opposite direction of +x

5 0
2 years ago
If a train is 100 kilometers away, how much sooner would you hear the train coming by listening to the rails (iron) as opposed t
Whitepunk [10]
From tables, the speed of sound at 0°C is approximately
V₁ = 331 m/s (in air)
V₃ = 5130 m/s (in iron)

Distance traveled is
d = 100 km = 10⁵ m

Time required to travel in air is
t₁ = d/V₁ = 10⁵/331 = 302.12 s

Time required to travel in iron is
t₂ = d/V₂ = 10⁵/5130 = 19.49 s

The difference in time is
302.12 - 19.49 = 282.63 s

Answer:  283 s (nearest second)



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Summary:
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