Two point charges separated by a distance d repel each other with a force of 9N. If the separation between them becomes 3d, the
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Answer:
The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Explanation:
Given that,
Distance between the slits = 0.04 mm
Width = 0.01 mm
Distance between the slits and screen = 1 m
Wavelength = 600 nm
We need to calculate the distance between the places where the intensity is zero due to the double slit effect
For constructive fringe
First minima from center
Second minima from center
The distance between the places where the intensity is zero due to the double slit effect
Put the value into the formula
Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2 .</u>
<u>Explanation:</u>
Here, we have Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Let's calculate which student’s measurement has the largest percent error :
<u>A. Student 4: 9.61 m/s2 </u>
Percentage of error = %.
<u>B. Student 3: 9.88 m/s2 </u>
Percentage of error = %.
<u>C. Student 2: 9.79 m/s2 </u>
Percentage of error = % .
<u>D. Student 1: 9.78 m/s2</u>
Percentage of error = % .
On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2 .</u>