Answer:
The arrow is at a height of 500 feet at time t = 2.35 seconds.
Explanation:
It is given that,
An arrow is shot vertically upward at a rate of 250 ft/s, v₀ = 250 ft/s
The projectile formula is given by :
We need to find the time(s), in seconds, the arrow is at a height of 500 ft. So,
On solving the above quadratic equation, we get the value of t as, t = 2.35 seconds
So, the arrow is at a height of 500 feet at time t = 2.35 seconds. Hence, this is the required solution.
Answer:
torque is 1.7 * Nm
Explanation:
Given data
turns n = 1000 turns
radius r = 12 cm
current I = 15A
magnitude B = 5.8 x 10^-5 T
angle θ = 25°
to find out
the torque on the loop
solution
we know that torque on the loop is
torque = N* I* A*B* sinθ
here area A = πr² = π(0.12)²
put all value
torque = N* I* A*B* sinθ
torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin25
torque = 0.0166 N m
torque is 1.7 * Nm
Answer:
The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Explanation:
Given that,
Distance between the slits = 0.04 mm
Width = 0.01 mm
Distance between the slits and screen = 1 m
Wavelength = 600 nm
We need to calculate the distance between the places where the intensity is zero due to the double slit effect
For constructive fringe
First minima from center
Second minima from center
The distance between the places where the intensity is zero due to the double slit effect
Put the value into the formula
Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Given:
Distance = 50 yard = 45.72 meter
Speed = 40 km/hr = 11.11 m/s
To find:
Time required by ball to reach the receiver = ?
Formula used:
speed =
Solution:
The speed of the ball is given by,
speed =
Thus,
Time =
Distance = 50 yard = 45.72 meter
Speed = 40 km/hr = 11.11 m/s
Time = 4.12 second
Hence, ball reaches the receiver in 4.12 second.