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skad [1K]
2 years ago
3

A ball is pushed with an initial velocity of 4.0 m/s. The ball rolls down a hill with a constant acceleration of 1.6 m/s2. The b

all reaches the bottom of the hill in 8.0 s. What is the ball's velocity at the bottom of the hill?
Physics
1 answer:
Marianna [84]2 years ago
4 0

Answer:

16.8 m/s

Explanation:

As the ball is subjected to a constant acceleration of 1.6m/s2 in 8 seconds before reaching the bottom of the hill, its increment in velocity must be

\Delta v = a\Delta t = 1.6 * 8 = 12.8 m/s

Since it was pushed with an initial velocity of 4m/s, its final velocity when reaching bottom of the hill is

v = v_0 + \Delta v = 4 + 12.8 = 16.8 m/s

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Answer:

Explanation:

Impulse = change in momentum

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Explanation:

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As there is no external force therefore momentum is conserved

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