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SVETLANKA909090 [29]
2 years ago
7

When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room. Which sentence explains t

his?
A.
Gases do not have a definite volume.
B.
The particles of gases are closely packed.
C.
The force of attraction between particles in gases is very high.
D.
Gases are not matter.
Physics
1 answer:
Vlada [557]2 years ago
3 0

A.

Gases do not have a definite volume.

Explanation:

This observation suggests that the gases do not have a definite volume. Gases moves randomly and will expand to take up the shape of containers they are introduced into.

  • The particles of a gas are very far apart.
  • They are held together by very weak attractive forces
  • Gases are random and they frequently collide with one another and the walls of the containers they are put into.
  • They have no fixed volumes

learn more:

Kinetic theory of matter brainly.com/question/12362857

#learnwithBrainly

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A projectile of mass 0.2 kg and an initial velocity of 50 m/s collides with the end of a blade attached to a turbine. The rotati
fgiga [73]

Answer:

5.5 rad/sec

Explanation:

8 0
2 years ago
A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it
vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

F = ma...(I)

Using formula of friction force

F= \mu m g....(II)

Put the value of F in the equation (II) from equation (I)

ma=\mu mg....(III)

a = \mu g

Put the value in the equation (III)

a=0.24\times9.8

a=2.352\ m/s^2

We need to calculate the distance,

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}2.352\times(3.0)^2

s=10.584\ m\ approx\ 11\ m

Hence, The distance is 11 m.

3 0
2 years ago
You slip a wrench over a bolt. Taking the origin at the bolt, the other end of the wrench is at x=18cm, y=5.5cm. You apply a for
mart [117]

Answer:

The torque on the wrench is 4.188 Nm

Explanation:

Let r = xi + yj where is the distance of the applied force to the origin.

Since x = 18 cm = 0.18 cm and y = 5.5 cm = 0.055 cm,

r = 0.18i + 0.055j

The applied force f = 88i - 23j

The torque τ = r × F

So, τ = r × F = (0.18i + 0.055j) × (88i - 23j) = 0.18i × 88i + 0.18i × -23j + 0.055j × 88i + 0.055j × -23j

= (0.18 × 88)i × i + (0.18 × -23)i × j + (0.055 × 88)j × i + (0.055 × -22)j × j  

= (0.18 × 88) × 0 + (0.18 × -23) × k + (0.055 × 88) × (-k) + (0.055 × -22) × 0   since i × i = 0, j × j = 0, i × j = k and j × i = -k

= 0 - 4.14k + 0.0484(-k) + 0

= -4.14k - 0.0484k

= -4.1884k Nm

≅ -4.188k Nm

So, the torque on the wrench is 4.188 Nm

8 0
2 years ago
The air surrounding an airplane in flight exerts a drag force that acts opposite to the airplane's motion. When an Airbus A380 i
Rainbow [258]

Answer:

4.32\cdot 10^5 hp, 3.22\cdot 10^8 W

Explanation:

The jet is flying at constant velocity: this means that its acceleration is zero, so the net force acting on the jet is also zero.

Therefore, we can write:

4F_T - F_d = 0

where

F_T = 322,000 N is the thrust force generated by each engine of the jet

F_d is the drag force

Solving for Fd,

F_d = 4 F_T = 4(322,000)=1.288\cdot 10^6 N

The velocity of the jet is

v=250 m/s

So, the rate at which the drag force does work (which is the power) is

P=F_d v

and substituting

F_d = 1.288\cdot 10^6 N\\v = 250 m/s

we find

P=(1.288\cdot 10^6)(250)=3.22\cdot 10^8 W

Converting into horsepower,

P=\frac{3.22\cdot 10^8}{746}=4.32\cdot 10^5 hp

4 0
2 years ago
A car came to a stop from a speed of 35 m/s in a time of 8.1 seconds. What was the acceleration of the car?
uranmaximum [27]
Simply subtract the two velocities and divide by 8.1,

\frac{0 - 35}{8.1} = - 4.32

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
5 0
2 years ago
Read 2 more answers
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