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2 years ago

The cube root of 0.000004913 is

Mathematics

1 answer:

Vlad1618 [11]2 years ago

4 0

Answer:

$\sqrt[3]{0.000004913}=0.017$

Step-by-step explanation:

Cubic Root

The cubic root of a number N is M, if

$M^3=N$

It's usually tedious to manually compute cubic roots, but if we use some basic algebra concepts, the job is easily done.

Let's compute

$M=\sqrt[3]{0.000004913}$

The argument can be expressed in scientific notation as

$0.000004913= 4913\ 10^{-9}$

The power of 10 has an exact cubic root since the exponent is a multiple of 3. To find the cubic root of the mantissa, we note it's the triple product of 17, i.e.

$4913=17*17*17=17^3$

Thus our number is

$M=\sqrt[3]{17^3\ 10^{-9}}=17\ 10^{-3}=0.017$

We have then

$\boxed{\sqrt[3]{0.000004913}=0.017}$

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Answer:

$(a)\ 0.0864$

$(b)\ 0.096$

$(c)\ 0.24$

$(d)\ 0.936$

Step-by-step explanation:

Given

$p \to$ close

$q \to$ fail to close

$p = 60\%$

$p = 0.60$

First, calculate the value of q

Using complement rule

$q = 1 - p$

$q = 1 - 0.60$

$q = 0.40$

So, we have:

$p = 0.60$ and $q = 0.40$

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

$Pr = 0.60^3*0.40$

$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

$Pr = 0.40^2 * 0.60$

$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

$Pr = 0.24$

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

$Pr' = 1- 0.40^3$

$Pr' = 1- 0.064$

$Pr' = 0.936$

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2 years ago

A population consists of the following five values: 1, 3, 4, 4, and 6. List all samples of size 2 from left to right without rep

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Answer:

The sample of sizes 2 and their mean are given below.

Step-by-step explanation:

The population consist of 5 values, S = {1, 3, 4, 4, 6}.

The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

${5\choose 2}=\frac{5!}{2!(5-2)!} =10$

Th formula to compute the mean is:

$\bar x=\frac{1}{n}\sum x_{i}$

List the 10 samples and their mean as follows:

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(1, 3) $\bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0$

(1, 4) $\bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5$

(1, 6) $\bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5$

(3, 4) $\bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5$

(3, 6) $\bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5$

(4, 4) $\bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0$

(4, 6) $\bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0$

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2 years ago

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Answer:

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B. 0.0473

Step-by-step explanation:

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with parameter λ=2, then P(X≥1) is equal to:

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D. 0.1353

with parameter λ=1.5, then P(2≤X≤4) is equal to

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B. 0.0473

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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serg [7]

Answer:

Step-by-step explanation:

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$\frac{12}{3000} \times2000$

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2 years ago

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