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storchak [24]
2 years ago
3

Quickly spinning the handle of a hand generator, Kevan is able to light three bulbs in a circuit. When he uses two batteries ins

tead of the generator, the bulbs are very dim. Which statement best explains why the batteries are not able to power all three light bulbs like the generator?
The batteries do not make the charges move as much
The generator creates less voltage
The batteries have higher amperage
The generator current is more steady
Physics
1 answer:
svlad2 [7]2 years ago
8 0

The batteries do not make the charges move as much

Explanation:

The problem here is that the batteries do not make the charges move as much. The battery has a low potential different between its terminal to derive the charges and produce current to light the bulb.

  • A battery is an electrochemical cell that converts chemical energy to electrical energy.
  • In a battery when there is an electronic movement via chemical reaction.
  • Electrical energy is produced the other way causing electric current.
  • The electromotive force of the cell, is the driving force for the current in a circuit.
  • It is the potential difference between the two electrodes when no current is flowing.
  • When a circuit is functioning and the bulbs are dim, it suggests that the there is little electromotive force to move them. The charges are not moving as such.

learn more:

Batteries brainly.com/question/8892837

#learnwithBrainly

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Answer:

Explanation:

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When the negatively charged half shell is brought in contact with the positively charged shell , the positive and negative charge present on each shell neutralises each other  .So both the shells lose their charges .The positive half shell also loses all its charges

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Hence, the maximum acceleration is calculated as follows.

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(b)  Since, 30% of the power is lost in the drive train. So, the new power is 70% of P_{max}.

That is,   new power = 0.7 \times P_{max}

Now, the expression for power in terms of force and velocity is as follows.

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Therefore, speed of the Porsche at maximum power output is as follows.

            \nu = 0.7 \times \frac{P_{max}}{ma_{max}}

                      = 0.7 \times \frac{217 hp \times \frac{746 W}{1 hp}}{1500 kg \times 6.53 m/s^{2}}

                      = 11.568 m/s

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Therefore, speed of the Porsche at maximum power output is 11.57 m/s.

(c)   The time taken will be calculated as follows.

             time = \frac{\text{velocity}}{\text{acceleration}}

                     = \frac{11.57 m/s}{6.53 m/s^{2}}

                     = 1.77 s

Therefore, the Porsche takes 1.77 sec until it reaches the maximum power output.

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