Mr. Golv is practicing his jiu-jitsu drill where he does 555 guard passes and 222 kimura arm locks. A guard pass takes GGG secon
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The volume of sphere can be calculated using the following formula:
Here, r is radius of the sphere which is 3.5 cm. Putting the value,
This is equal to the volume of lead, density of lead is thus, mass of lead can be calculated as follows:
m=d×V
Putting the values,
Let the mass of ore be 1 g, 68.6% of galena is obtained by mass, thus, mass of galena obtained will be 0.686 g.
Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:
m=0.686×0.866=0.5940 g
Therefore, 0.5940 g of lead is obtained from 1 g of ore for 100% efficiency, thus, for 92.5% efficiency
1 g of lead obtain from grams of ore.
Thus, 2041.2 g of lead obtain from:
Therefore, mass of ore required to make lead sphere is 3.715 kg.