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miskamm [114]
2 years ago
7

A person is making homemade ice cream. She exerts a force of magnitude 29 N on the free end of the crank handle on the ice-cream

maker, and this end moves on a circular path of radius 0.30 m. The force is always applied parallel to the motion of the handle. If the handle is turned once every 1.5 s, what is the average power being expended
Physics
1 answer:
Vaselesa [24]2 years ago
4 0

Answer:

P = 36.44 W.

Explanation:

given,

force = 29 N

Radius of circular path, R = 0.30 m

time = 1.5 s

Average Power, P = ?

Work done = F .s

displacement, s = 2 π r

         s = 2 π x 0.30 = 0.6 π

W = F .s

W = 29 x 0.6 x π

W = 54.66 J

now,

Power = \dfrac{Work\ done}{time}

Power = \dfrac{54.66}{1.5}

   P = 36.44 W.

The average power of the Person is equal to 36.44 W.

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One of the great dangers to mountain climbers is an avalanche, in which a large mass of snow and ice breaks loose and goes on an
sammy [17]

Answer:

Explanation:

The acceleration of an object down a slope (neglecting friction, µ = 0) is:

a = g × sin θ

Where,

g is the acceleration due to gravity and θ is the angle of the slope.

a = (9.8 × sin (21.5º)

= 3.592 m/s²

Using equations of motion,

S = ut + 1/2at²

Since, u = 0,

S = 1/2at²

347 = 1/2 × (3.592)t²

t² = 193.21

= sqrt(193.21)

= 13.9 s.

5 0
2 years ago
Someone plans to float a small, totally absorbing sphere 0.500 m above an isotropic point source of light,so that the upward rad
mote1985 [20]

Answer:

468449163762.0812 W

Explanation:

m = Mass = \rhoV

V = Volume =\dfrac{4}{3}\pi r^3

r = Distance of sphere from isotropic point source of light = 0.5 m

R = Radius of sphere = 2 mm

\rho = Density = 19 g/cm³

c = Speed of light = 3\times 10^8\ m/s

A = Area = \pi R^2

I = Intensity = \dfrac{P}{4\pi r^2}

g = Acceleration due to gravity = 9.81 m/s²

Force due to radiation is given by

F=\dfrac{IA}{c}\\\Rightarrow F=\dfrac{\dfrac{P}{4\pi r^2}{\pi R^2}}{c}\\\Rightarrow F=\dfrac{PR^2}{4r^2c}

According to the question

F=mg\\\Rightarrow \dfrac{PR^2}{4r^2c}=\rho \dfrac{4}{3}\pi R^3g\\\Rightarrow P=\dfrac{16r^2\rho c\pi Rg}{3}\\\Rightarrow P=\dfrac{16\times 0.002\times 19000\times \pi\times 0.5^2\times 9.81\times 3\times 10^8}{3}\\\Rightarrow P=468449163762.0812\ W

The power required of the light source is 468449163762.0812 W

4 0
2 years ago
Which of the following substances will show the smallest change in temperature when equal amounts of energy are absorbed?
SSSSS [86.1K]
It would be water because if you freeze it than you will still be able to see it and if you boil it than you will be able to see it disappear.
3 0
2 years ago
Read 2 more answers
A particle decelerates uniformly from a speed of 30 cm/s to rest in a time interval of 5.0 s. It then has a uniform acceleration
wel

Answer:

V=20cm/s

Explanation:

The average speed is the distance total divided the time total:

V=X/T

First stage:

T1=5s

v_{f}  =v_{o} - at

But, v_{f}  =0   (decelerates to rest)

then: a =v_{o} /t=0.3/5=0.06m/s^{2}

on the other hand:

x =v_{o}*t - 1/2*at^{2}=0.3*5-1/2*0.06*5^{2}=0.75m

X1=75cm

Second stage:

T2=5s

x =v_{o}*t + 1/2*at^{2}=0+1/2*0.1*5^{2}=1.25m

X2=125cm

Finally:

X=X1+X2=200cm

T=T1+T2=10s

V=X/T=20cm/s

8 0
2 years ago
Calculate the average velocity in m/y of a tectonic plate that has travelled 9000 km to the south in 60 million years
Gekata [30.6K]
<span>The distance covered by the tectonic plate, in meters, is
</span>d=9000km=9\cdot 10^6 m<span>
 The time taken for the tectonic plate to cover this distance is equal to
</span>t=60 mil.y=60 \cdot 10^6 y<span>
Therefore, the average velocity of the tectonic plate is the ratio between the distance covered and the time taken: 
</span>v= \frac{S}{t} = \frac{9\cdot 10^6m}{60 \cdot 10^6y} =0.15 m/y.<span>
</span>
8 0
2 years ago
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