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Zielflug [23.3K]

2 years ago

14

the coefficient of static friction between a 40 kg picnic table and the ground below is .43. what is the greatest horizontal for

ce that could be exerted on the table while it remains stationary?

2 answers:

Mashcka [7]2 years ago

6 0

Answer:

The greatest horizontal force that can be exerted without moving the table is 168.56N.

Explanation:

The maximum friction force is determined from the coefficient of static friction as follows:

$F_{fr}=\mu\cdot F_{norm} = 0.43\cdot F_{norm}$

where the the normal force is exerted by the ground as a reaction to the weight of the table, and has same magnitude as but opposite direction to the gravitational force on the table:

$F_{fr} = 0.43\cdot 40kg\cdot 9.8 \frac{m}{s^2} = 168.56 N$

This is the <em>maximum</em> static force, so the friction force will be matching and opposing any horizontal force up to 168.56N.

Gre4nikov [31]2 years ago

4 0

The force equals the coefficient of static friction times the weight. Use gravity g=9.8 m/s^2
0.43*40*9.8=16.856 N

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If we analyze the situation, we need to have an aceleretarion greater than cero. We are going to choose a = 1.67m/s^2

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2 years ago