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JulsSmile [24]
2 years ago
10

For each of the following integrals, indicate whether integration by substitution or integration by parts is more appropriate, o

r if neither method is appropriate. Do not evaluate the integrals.
a. ∫ xSinx dx
i. substitution
ii. neither
iii.integration

b. ∫ x⁴/(1+x³). dx
i. substitution
ii. neither
iii.integration

c. ∫ x⁴. e^x³. dx
i. substitution
ii. neither
iii.integration

d. ∫x⁴ cos(x⁵). dx
i. substitution
ii. neither
iii.integration

e. ∫1/√9x+1 .dx
i. substitution
ii. neither
iii.integration
Mathematics
1 answer:
Andrei [34K]2 years ago
6 0

Answer:

a. ∫ xSinx dx

iii. integration by parts

u =x and dv= sinx

b. ∫ x⁴/(1+x³). dx  

ii. neither

Long division is an option here before integration is done

c. ∫ x⁴. e^x³. dx

i. substitution

where u = x⁵

d. ∫x⁴ cos(x⁵). dx

i. substitution

where u = x⁵

e. ∫1/√9x+1 .dx

i. substitution

where u = 9x+1

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If mBC = (9x-53) and mCD = (2x + 45) find mBAD
Rom4ik [11]

Answer:

m\angle BAD=73^o

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the value of x

Let

O ----> the center of the circle

we know that

Triangle BOC≅Triangle COD

m\angle BOC=arc\ BC ----> by central angle

m\angle COD=arc\ CD ----> by central angle

m\angle BOC=m\angle COD

therefore

arc\ BC=arc\ CD

substitute the given values

(9x-53)^o=(2x+45)^o

solve for x

9x-2x=45+53\\7x=98\\x=14

step 2

Find the measure of angle BAD

we know that

The inscribed angle is half that of the arc it comprises.

so

m\angle BAD=\frac{1}{2} [arc\ BC+arc\ CD]

arc\ BC=9(14)-53=73^o

arc\ CD=2(14)+45=73^o

substitute

m\angle BAD=\frac{1}{2} [73^o+73^o]=73^o

7 0
2 years ago
(25 points, please help! Brainliest!) Mrs. Hanger is painting the following picture of an H to hang in the entryway of her home.
disa [49]

Answer:

the new scale is the same length as the original scale

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40 POINTS!!!!! A submarine descends to 1/6 of its maximum depth. Then it descends another 2/3 of its maximum depth. If it is now
tia_tia [17]
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4 0
2 years ago
Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
2 years ago
In triangle XYZ, XY = 13, YZ=20, and XZ=25. What is the measure of angle Z to the nearest degree?
anastassius [24]
We can use Law of Cosines to solve for the angle of Z. The solution is shown below:
cos C=(a²+b²-c²)/2ab
cos Z = (yz² + xz² - xy² )/2*yz*xz
cos Z = (20² + 25  - 13²)/2*20*25
cos Z = 856 / 1000
Z=31.13°

The answer is angle 31.13°. 
4 0
2 years ago
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