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JulsSmile [24]
1 year ago
10

For each of the following integrals, indicate whether integration by substitution or integration by parts is more appropriate, o

r if neither method is appropriate. Do not evaluate the integrals.
a. ∫ xSinx dx
i. substitution
ii. neither
iii.integration

b. ∫ x⁴/(1+x³). dx
i. substitution
ii. neither
iii.integration

c. ∫ x⁴. e^x³. dx
i. substitution
ii. neither
iii.integration

d. ∫x⁴ cos(x⁵). dx
i. substitution
ii. neither
iii.integration

e. ∫1/√9x+1 .dx
i. substitution
ii. neither
iii.integration
Mathematics
1 answer:
Andrei [34K]1 year ago
6 0

Answer:

a. ∫ xSinx dx

iii. integration by parts

u =x and dv= sinx

b. ∫ x⁴/(1+x³). dx  

ii. neither

Long division is an option here before integration is done

c. ∫ x⁴. e^x³. dx

i. substitution

where u = x⁵

d. ∫x⁴ cos(x⁵). dx

i. substitution

where u = x⁵

e. ∫1/√9x+1 .dx

i. substitution

where u = 9x+1

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galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

4 0
2 years ago
At a certain store, juice A cost $0.10 more per ounce than juice B. If a 12-ounce bottle of juice A cost $5.64, what is the cost
Olenka [21]

Answer:

C

Step-by-step explanation:

5.64/12= .47 but that box cost 10cents more than box B so you then you subtract .10 and get .37 per ounce for box B

7 0
1 year ago
Tyler is planning to buy a new car. He intends to trade in his existing car, a 2002 Chrysler Sebring in good condition. Using th
alexdok [17]

Answer:

a. $3,260.

Step-by-step explanation:

Tyler is planning to buy a new car. He intends to trade in his existing car, a 2002 Chrysler Sebring in good condition. Using the table below, we need to estimate about how much Tyler’s car is worth.

Given table is

Model/Year 2000    2001   2002   2003   2004

Pacifica   $2,194  $2,288 $2,605 $2,690 $2,814

Concorde   $1,842  $1,998 $2,180 $2,781 $2,925

Sebring    $2,920  $3,075 $3,260 $3,551 $3,912

300M       $2,770  $2,934 $3,095 $3,188 $3,676


Given choices are:

a. $3,260

b. $2,920

c. $2,605

d. $3,188


"2002 Chrysler Sebring" means look for the column of table which has year 2002. Then look for the row of the table which says "Sebring". Now we see that both rows and columns intersect at value $3,260.

Hence final answer is a. $3,260.

6 0
1 year ago
Read 2 more answers
Erin and Ethan add the fractions 2 and 1 z. Look at
LUCKY_DIMON [66]

Answer:

They are both the exact same, just one is simplified, and the other is still not simplified all the way. These two answers are exactly the same.

Step-by-step explanation:

5 0
1 year ago
`bar(JK)` is dilated by a scale factor of n with the origin as the center of dilation, resulting in the image `bar(J'K')`. The s
dalvyx [7]

Answer:

Length of Bar JK=l

Bar (JK) is dilated by a scale factor of n, having origin as the center of dilation.

New line segment formed named  bar (J'K').

As given slope of bar(JK) =m

When we dilate a line segment with respect to origin , having origin as the center of dilation, there is no effect of slope on Dilation.

Length of bar (J'K')= (Length of bar JK)×(Scale factor)

                             = l×n Or n×l

Option (D) is correct.

                           




7 0
2 years ago
Read 2 more answers
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