Question

During a workout at the gym, you set the treadmill at a pase of 55.0 m/min. How many minutes will you walk if you cover a distance of 7500 ft? ...?

Answer 1

Answer:

t = 41.56 min

Explanation:

As we know that the distance moved on the trade mill is given as

$d = 7500 ft$

here we know that

$1 ft = 12 inch$

$1 inch = 2.54 cm$

so we have

$1 ft = 12 \times 2.54 cm$

$1 ft = 0.3048 m$

now we know that

$d = 7500 \times 0.3048 m$

$d = 2286 m$

now we know that the speed on the trade mill is given as

$v = 55 m/min$

so time taken to move the given distance is

$t = \frac{d}{v}$

$t = \frac{2286}{55}$

$t = 41.56 min$

Answer 2

Here is the answer to the given problem above.
Given that you set the treadmill at a pace of 55meters/min, and we want to know how long will you be able to cover 7500 feet, the first thing we need to do is to convert 7500 to meters and we get 2286 meters. Next is we divide this by 55 and we get, 41.56. Therefore, the number of minutes that it will take to walk 7500 feet is 41.6 minutes. Hope this answer helps.