This question is incomplete. Luckily, I found the same problem which is shown in the attached picture. To answer the question, we must know how the size and charge affect the lattice energy. The answer is: lattice energy increases with the increasing charge of the ions, and decreasing radius of the atoms.
<em>Therefore, the ranking would be: A < B < C</em>.
<u>Answer:</u> The below calculations proves that the rate of diffusion of
is 0.4 % faster than the rate of diffusion of 
<u>Explanation:</u>
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

We are given:
Molar mass of 
Molar mass of 
By taking their ratio, we get:


From the above relation, it is clear that rate of effusion of
is faster than 
Difference in the rate of both the gases, 
To calculate the percentage increase in the rate, we use the equation:

Putting values in above equation, we get:

The above calculations proves that the rate of diffusion of
is 0.4 % faster than the rate of diffusion of 
To answer this question, you just need to put all the variable into <span>PV = nRT formula. In this case, the pressure(P) is 2.5 atm, the number of molecule(n) is 1.3 mol, the temperature(T) is 22 celcius= 295.15 kelvin.
Then the volume should be:
</span><span>PV = nRT
</span>2.5 * V = 1.3 * <span>0.08206* 295.15
</span>V= 12.59L
There are three critical constants namely, critical temperature, critical pressure and critical volume.
Critical temperature is defined as temperature of gas below which the increase in pressure cause liquefaction of gas and above that liquefaction of gas do not take place.
Critical pressure is defined as pressure needed to liquefy a gas at critical temperature. Volume of 1 mol of gas at critical pressure and temperature is known as critical volume.
Critical temperature can be calculated as follows:

Putting the value,

Thus, critical temperature is 564.88 K.
Critical pressure is calculated as follows:

Putting the values,

Therefore, critical pressure is 50.41 atm.
Now, calculate critical volume as follows:

Putting the values,

Therefore, for 1 mol critical volume is 0.345 L.