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Lady_Fox [76]
2 years ago
8

Tia and Sam want to see who is more precise at cutting paper. Each person cut 10 pieces of paper, and the lengths of their cuts

in inches are given below. Whose cuts had less variability in length?
Tia: 2.3, 2.4, 2.3, 2.5, 2.8, 2.4, 2.5, 2.3, 2.5
Sam: 2.0, 2.2, 2.1, 2.4, 2.3, 2.4, 2.6, 2.5, 2.4, 2.3
Mathematics
2 answers:
11Alexandr11 [23.1K]2 years ago
5 0

You did not provide 10 cuts for Tia. This problem cannot be solved.

ololo11 [35]2 years ago
4 0
Sam is the correct ant
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Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take
MrRissso [65]

Answer:

mean (μ) = 4.25

Step-by-step explanation:

Let p = probability of a defective computer components = \frac{68}{400} = 0.17

let q = probability of a non-defective computer components = \frac{332}{400} = 0.83

Given random sample n = 25

we will find mean value in binomial distribution

The mean of binomial distribution = np

here 'n' is sample size and 'p' is defective components

mean (μ) = 25 X 0.17 = 4.25

<u>Conclusion</u>:-

mean (μ) =  4.25

6 0
2 years ago
A statistics professor drew a random sample of 81 observations and found that x with bar on top equals 62 s equals 15. Estimate
ratelena [41]

Answer:

LCL = 59.26 to two decimal places

Step-by-step explanation:

Here, we want to estimate the LCL of the population mean with 90% confidence

We proceed as follows;

Given alpha = 0.1, then Z(0.05)=1.645 (from standard normal table), s = 15

Mathematically;

LCL =x_bar -Z*s/√( n)= 62 - (1.645 * 15)/√81

LCL = 62- (24.675)/9 = 59.2583

LCL = 59.26 to two decimal places

3 0
2 years ago
Solve the system of linear equations. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.
earnstyle [38]

Answer:x1 = - 2.5

x2 = 29

x3 = 10

Step-by-step explanation:

2x1 + x2 − 2x3 = 4 - - - - - - - - - - 1

4x1 + 2x3 = 10 - - - - - - - - - - - - - 2

−4x1 + 5x2 − 17x3 = −15 - - - - - - - 3

Adding equation 2 to equation 3, it becomes

5x2 - 15x3 = - 5 - - - - - - - - - - -;-4

Multiplying equation 1 by 4 and equation 3 by 2, it becomes

8x1 + 4x2 − 8x3 = 16

8x1 + 10x2 − 34x3 = −30

Subtracting

- 6x2 + 26x3 = 46- - - - - - - - - - - - 5

Multiplying equation 4 by 6 and equation 5 by 5, it becomes

30x2 - 90x3 = - 30

- 30x2 + 130x3 = 230

Adding, it becomes

20x3 = 200

x3 = 200/20 = 10

Substituting x3 = 10 into equation 4, it becomes

5x2 - 15 × 10 = - 5

5x2 - 150 = - 5

5x2 = - 5 + 150 = 145

x2 = 145/5 = 29

Substituting x3 = 10 into equation 2, it becomes

4x1 + 2 × 10 = 10

4x1 = 10 - 20 = - 10

x1 = - 10/4 = - 2.5

4 0
2 years ago
Declan needs euros to go on holiday. He can buy 46 euros for £40. How much will 805 euros cost at the same rate?
kobusy [5.1K]

Answer:

700 pounds

Step-by-step explanation:

if 46 euros cost 40 pounds

then 805 euros will cost 805 multiplied 40

whatever answer you get divide it by 46

6 0
2 years ago
Points a, b, and c are midpoints of the sides of right triangle def. Which statements are true select three options. A B C D E
bagirrra123 [75]

Answer : The correct statements are,

AC = 5 cm

BA = 4 cm

The perimeter of triangle ABC is 12 cm.

Step-by-step explanation :

As we know that a, b, and c are midpoints of the sides of right triangle that means midpoint divide the side in equal parts.

Now we have to calculate the sides of triangle ABC by using Pythagoras theorem.

Using Pythagoras theorem in ΔACF :

(AC)^2=(FA)^2+(CF)^2

Now put all the values in the above expression, we get the value of side AC.

(AC)^2=(3)^2+(4)^2

AC=\sqrt{(9)^2+(16)^2}

AC=5cm

Using Pythagoras theorem in ΔDAB :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(BD)^2=(AD)^2+(BA)^2

Now put all the values in the above expression, we get the value of side BA.

(5)^2=(3)^2+(BA)^2

BA=\sqrt{(5)^2-(3)^2}

BA=4cm

Using Pythagoras theorem in ΔBEC :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(BE)^2=(CE)^2+(CB)^2

Now put all the values in the above expression, we get the value of side CB.

(5)^2=(4)^2+(CB)^2

CB=\sqrt{(5)^2-(4)^2}

CB=3cm

Now we have to calculate the perimeter of ΔABC.

Perimeter of ΔABC = Side AB + Side CB+ Side AC

Perimeter of ΔABC = 4 + 3 + 5

Perimeter of ΔABC = 12 cm

Now we have to calculate the area of ΔABC.

Area of ΔABC = \frac{1}{2}\times 4\times 3=6cm^2

Now we have to calculate the area of ΔDEF.

Area of ΔDEF = \frac{1}{2}\times 8\times 6=24cm^2

Area of ΔABC = \frac{6}{24}\times Area of ΔDEF

Area of ΔABC = \frac{1}{4} Area of ΔDEF

8 0
2 years ago
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