answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andre [41]
2 years ago
8

Incoming solar radiation (light energy) is absorbed by the Earth's surface and converted to outgoing infrared radiation (heat en

ergy). Since energy can neither be created nor destroyed, if more energy enters the Earth's climate system than leaves it, a net disequilibrium in the Earth's energy balance would result in __________.
Physics
1 answer:
AVprozaik [17]2 years ago
8 0

Answer:

Increase in Temperature (Global warming)

Explanation:

Incoming solar radiation is converted into heat energy and absorbed by the Earth's surface. The law of conservation of energy says that energy can neither be created nor destroyed but rather changes from one form to another. Now if more and more energy enters the Earth's surface and very little portion of it leaves the Earth's surface then a net disequilibrium in the energy balance will result in increased temperature because Earth is absorbing much more heat than it should!

One of the key factors of this unbalance is the pollution created by burning fossil fuels. Burning fossil fuels releases Carbon Dioxide CO2 and other pollutants.

Usually the leftover incoming solar radiation after being absorbed by the earth would escape back to the space but CO2 and other pollutants trap and absorb this radiation and thus, increases the Earth's temperature.  

You might be interested in
A 25-mm-diameter uniform steel shaft is 600 mm long between bearings. (7-33) (9 Pts) A. Find the lowest critical speed of the sh
Arte-miy333 [17]

Answer:

a = the lowest critical speed of the shaft 882.81 rad/s

b = new diameter 0.05m or 50mm

c = critical speed 1765.62rad/s

Explanation:

see the attached file

8 0
2 years ago
8.4-1 Consider a magnetic field probe consisting of a flat circular loop of wire with radius 10 cm. The probe’s terminals corres
Vlad1618 [11]

Answer:

B_o = 1.013μT

Explanation:

To find B_o you take into account the formula for the emf:

\epsilon=-\frac{d\Phi_b}{dt}=-\frac{dBAcos\theta}{dt}=-Acos\theta\frac{dB}{dt}

where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.

By applying the derivative you obtain:

\epsilon=-Acos\theta (2\pi f) B_ocos(2\pi f t+ \alpha)

when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:

\epsilon=2\pi fAB_o=2\pi (100*10^3Hz)(\pi (0.1m)^2)B_o=19739.20Hzm^2B_o\\\\B_o=\frac{20*10^{-3}V}{19739.20Hzm^2}=1.013*10^{-6}T=1.013\mu T

hence, B_o = 1.013μT

6 0
2 years ago
A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0s. How strong must the rope be? μk
Leokris [45]

Answer:

The rope must have a force of 10084,21 N

Explanation

Acceleration calculation

The car acceleration is equal to the acceleration of the truck

ac: car acceleration\frac{m}{s^{2} }

at: truck acceleration\frac{m}{s^{2} })

ac = at= \frac{vf-vi}{t-ti}  equation(1)

Known information:

vi = Initial speed = 0, ti = initial time = 0

vf = Final speed = 13 \frac{m}{s}, t = final time =5 s

We replaced the known information in the equation(1):

ac = at = \frac{13-0}{15-0}

ac=ac=\frac{13}{15}  \frac{m}{s}

Dynamic analysis

The forces acting on the car are the following:

Wc: Car weight

N: normal force, road force on the car

Ff: Friction force

T: Force of tension

Car weight calculation:

Wc=mc*g

mc = Car mass = 2230kg

g = Gravity acceleration=9.8 \frac{m}{s^{2} }

Wc= 2230*9.8

Wc=21854 N

Normal force calculation:

Newton's first law

sum Fy= 0

N-W=0

N=W

N=21854 N

Friction force calculation (Ff):

We have the formula to calculate the friction force:

Ff = μk * N  Equation (3)

μk kinetic coefficient of friction

We know that μk = 0.373and N= 21854N ,then:

Ff=0.373*21854

Ff=8151.54 N

Calculation of the tension force in the rope (T):

Newton's Second law

sum Fx= mc*ac

T-Ff=mc*ac

T=2230(\frac{13}{15}) + 8151.54

T=10084,21 N

Answer: The rope must have a force of 10084,21 N

8 0
2 years ago
A 57 kg paratrooper falls through the air. How much force is pulling him down?
just olya [345]

Answer:

Explanation:

Force = Mass * acceleration due to gravity.

Given

Mass of the paratrooper = 57kg

Acceleration due to gravity = 9.81m/s²

Required

Force pulling him down

Substitute unto formula;

F = 57 * 9.81

Force = 559.17 N

Hence the force pulling him down is 559.17N

7 0
2 years ago
A Martian rover is descending a hill sloped at 30° with the horizontal. It travels with a constant velocity of 2 meters/second.
kodGreya [7K]
Vx = 2*cos30 = 1.73m's
Other words:
D = Vo*t = 1.4 * 21 = 31.5m. @ 30 Deg.
Dy = 31.5*sin30 = 15.75 m.
8 0
2 years ago
Read 2 more answers
Other questions:
  • Your boss asks you to design a room that can be as soundproof as possible and provides you with three samples of material. The o
    11·2 answers
  • In a digital multimeter, what changes inside the meter when you push the button to change from 200v range to the 20v range? by w
    7·1 answer
  • _____ discovered that light also showed properties commonly found in waves.
    8·2 answers
  • What type of weather modification involves the use of large fans to mix surface air with air aloft?
    12·1 answer
  • A block with mass m = 7 kg is attached to two springs with spring constants kleft = 37 N/m and kright = 48 N/m. The block is pul
    9·1 answer
  • A sample of an unknown volatile liquid was injected into a Dumas flask (mflask = 27.0928 g, Vflask = 0.1040 L) and heated until
    10·1 answer
  • Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc
    6·1 answer
  • Water (cp = 4180 J/kg·K) is to be heated by solar-heated hot air (cp = 1010 J/kg·K) in a double-pipe counter-flow heat exchanger
    15·1 answer
  • The air in a pipe resonates at 150 Hz and 750 Hz, one of these resonances being the fundamental. If the pipe is open at both end
    6·1 answer
  • A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide pa
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!