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lorasvet [3.4K]
2 years ago
13

John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. He is pulling horizontally wi

th a constant force of 400 N. John and manages to get the sled going from 0 to 4 m/s in 5 s. The force due to friction on the sled is 310 N. What is the mass of Laura and the sled combined?
Physics
1 answer:
bulgar [2K]2 years ago
4 0

Answer:

The mass of Laura and the sled combined is 887.5 kg

Explanation:

The total force due to weight of Laura and friction on the sled can be calculated as follows;

F_T = F_L+F_S

     = (400 + 310) N

     = 710 N

From Newton's second law of motion, "the rate of change of momentum is directly proportional to the applied force.

F_T = \frac{(M_L+M_S)V}{t}

where;

M_L is mass of Laura and

M_S is mass of sled

Mass of Laura and the sled combined is calculated as follows;

(M_L+M_S) = \frac{F_T*t}{V}

given

V = Δv = 4-0 = 4m/s

t = 5 s

(M_L+M_S) = \frac{710*5}{4}\\\\(M_L+M_S) =  887.5 kg

Therefore, the mass of Laura and the sled combined is 887.5 kg

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The density of the fluid is 1100 kg/m³.

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Given that,

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Using formula of pressure for density

\Delta P = \rho g h

\rho =\dfrac{\Delta P}{gh}

Where, \rho = density

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Put the value in to the formula

\rho =\dfrac{539}{5.00\times10^{-2}\times9.8}

\rho =1100\ kg/m^3

Hence, The density of the fluid is 1100 kg/m³.

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Point charge A with a charge of +4.00 μC is located at the origin. Point charge B with a charge of +7.00 μC is located on the x
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If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the
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Now, using Newton's first law of motion, we can find acceleration (a). Thus;

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Inna Hurry is traveling at 6.8 m/s, when she realizes she is late for an appointment. She accelerates at 4.5 m/s^2 for 3.2 s. Wh
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Answer:

1) v = 21.2 m/s

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The acceleration of Inna, a = 4.5 m/s²

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2) Given,

The initial velocity of Lisa, u = 12 m/s

The final velocity of Lisa, v = 26 m/s

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Hence, the deceleration of the car, a = = -4.32 m/s²

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