Complete question:
The classic Goodyear blimp is essentially a helium balloon— a big one, containing 5700 m³ of helium. If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? Assume an air temperature of 20°C.
Answer:
52.4 kN
Explanation:
The helium at 20°C has a density of 0.183 kg/m³, and the cargo load is the weight of the system, which consists of the envelope, the gondola, and the helium.
The helium mass is the volume multiplied by the density, thus:
mHe = 5700 * 0.183 = 1043.1 kg
The total mass is then 5343.1 kg. The weight is the mass multiplied by the gravity acceleration (9.8 m/s²), so:
W = 5343.1*9.8
W = 53362.38 N
W = 52.4 kN
Answer:
C
Explanation:
If the arrows represent light rays, then Rachel sees a candle flame when the light released by the flame is received by her eyes.
Answer:
As shown in the attachment
Explanation:
The detailed steps and mathematical assumptions and manipulation is as shown in the attachment.
Answer:
f1 / f2 = n2 / n1
Explanation:
To solve this problem, we should remember that the formula for index of refraction is defined as:
n = c / v
or
n v = c
Where,
n = index of refraction
c = speed of light
v = speed of light in the medium
Since speed of light is constant, then we can simply equate the materials 1 and 2:
n1 v1 = n2 v2
Where the speed of light in the medium (v) can be expressed as:
v = w * f
Where,
w = wavelength of light
f = frequency of light
Therefore substituting this back into the relating equation:
n1 w1 f1 = n1 w2 f1
Since it is given that the light is monochromatic, w1 = w2, this further simplifies the equation to:
n1 f1 = n2 f2
f1 / f2 = n2 / n1 (ANSWER)
