Question

A conducting rod (length = 80 cm) rotates at a constant angular rate of 15 revolutions per second about a pivot at one end. A uniform field (B = 60 mT) is directed perpendicularly to the plane of rotation. What is the magnitude of the emf induced between the ends of the rod?

Answer 1

Answer:

3.62 V

Explanation:

L = 80 cm = 0.8 m

f = 15 rps

B = 60 m T = 0.060 T

ω = 2 x π x f = 2 x 3.14 x 15 = 94.2 rad/s

v = r ω

here, r be the radius of circular path. Here r = length of rod = L

v = 0.80 x 94.2 = 75.36 m/s

The motional emf is given by

e = B  v  L = 0.060 x 75.36 x 0.8 = 3.62 V