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Alexxandr [17]
2 years ago
11

The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. the heat increased the _

____ of the air in the room, which means an increase in the air's molecular kinetic energy.
Physics
2 answers:
uranmaximum [27]2 years ago
6 0
<h2>Apartment Explosion Reported </h2>

The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. The heat increased the temperature of the air in the room, which means an increase in the air's molecular kinetic energy.

When heat is provided then temperature increases and the molecules of substances move rapidly by increase of kinetic energy (K.E) temperature increases. It is understood that heat increases temperature.

Nat2105 [25]2 years ago
3 0

Answer: Temperature or Pressure

Explanation:

We need to complete the next:

"The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. the heat increased the _____ of the air in the room, which means an increase in the air's molecular kinetic energy."

We can suppose the air as an ideal gas, which is defined by the equation:

PV = nRT

where P is pressure, V is volume and T is temperature (n, the number of particles, and R are constants)

Here, if the temperature of the air, T, increases, then the product PV must also increase.

This means that the volume and pressure increases (first increases the volume, until the walls don't let ani more expansion, in this point the pressure starts to increase) In this case the volume is fixed (is the volume of the apartment) so the only things that can change are the pressure and the temperature.

This expansion is the "wave" created by the explosion and is the "destructive" part of the explosion.

The word that best can complete the statement is Pressure, but Temperature

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lbvjy [14]

Answer:

6.5 m/s^2

Explanation:

The net force acting on the yo-yo is

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net torque acting on the yo-yo is

τ_net = Iα

I= moment of inertia (= 0.5 mr^2 )

α = angular acceleration

τ_net = 0.5mr^2(a/r)

Tr= 0.5mr^2(a/r)

(mg-ma)r=0.5mr^2(a/r)

a(1/2+1)=g

a= 2g/3

a= 2×9.8/3 = 6.5 m/s^2

4 0
2 years ago
A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Ass
Vlada [557]
1) 15 / 12 = 1.25 ratio
2) to increase acceleration  1.25 times (with same F, or same engine) you have to lower mass 1.25 times
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2 years ago
Solve the equation x=3logy2 for y.
melisa1 [442]

X = 3 · log(Y²)

X = 3 · 2·log(Y)

X/6 = log(Y)

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2 years ago
Read 2 more answers
A 2200 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full pow
leonid [27]

Answer:

a) The maximum possible acceleration the truck can give the SUV is 7.5 meters per second squared

b) The force of the SUV's bumper on the truck's bumper is 18000 newtons

Explanation:

a) By Newton's second law we can find the relation between force and acceleration of the SUV:

F=ma

With F the maximum force the truck applies to the SUV, m the mass of the SUV and a the acceleration of the SUV; solving for a:

a=\frac{F}{m}=\frac{18000}{2400}\approx7.5\,\frac{m}{s^{2}}

b) Because at this acceleration the truck's bumper makes a force of 18000 N on the SUV’s bumper by Third Newton’s law the force of the SUV’s bumper on the truck’s bumper is 18000 N too because they are action-reaction force pairs.

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2 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
3 0
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