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Alexandra [31]
2 years ago
3

A column of some gas is open at one end and closed at the other. The shortest length of such a column that will resonate with a

350 Hz tuning fork is 28.0 cm. What is the speed of sound in this gas?
Physics
1 answer:
andrezito [222]2 years ago
7 0

Answer:

392 m/s

Explanation:

In a closed pipe or column (one in which one end is open and the other is closed), resonance occurs at various lengths of the column depending on the frequency. The shortest column is formed when the frequency is the fundamental frequency.

At any frequency, the node of the standing wave is formed at the closed end while antinodes are formed at the open end. For the fundamental frquency, this standing wave is a quarter-wavelength long since this is the shortest distance between a node and antinode.

Thus, l = \dfrac{\lambda}{4}

\lambda = 4l

Now the speed of a wave is

v=f\lambda where f is its frequency

Hence, v=f\times4l=4fl

Substituting values in the question and converting cm to m,

v=4\times 350\times 0.28 = 392 \text{ m/s}

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MrRa [10]
Convection can best be observed as she blows the warm steam air that rises.

As the warm steam rises,  she forces displaces it with cool air from her mouth. Because the warm steam is less dense it rises and because the cool air is more dense, it displaces the warm air.

This scenario is an example of convection.
 
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2 years ago
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An air-track cart with mass m1=0.28kg and initial speed v0=0.75m/s collides with and sticks to a second cart that is at rest ini
arsen [322]
Kinetic energy is calculated through the equation,

   KE = 0.5mv²

At initial conditions,

  m₁:  KE = 0.5(0.28 kg)(0.75 m/s)² = 0.07875 J

  m₂ : KE = 0.5(0.45 kg)(0 m/s)² = 0 J

Due to the momentum balance,

   m₁v₁ + m₂v₂ = (m₁ + m₂)(V)

Substituting the known values,

   (0.29 kg)(0.75 m/s) + (0.43 kg)(0 m/s) = (0.28 kg + 0.43 kg)(V)

   V = 0.2977 m/s

The kinetic energy is,
   KE = (0.5)(0.28 kg + 0.43 kg)(0.2977 m/s)²
   KE = 0.03146 J

The difference between the kinetic energies is 0.0473 J. 
7 0
2 years ago
Suppose you want to make a scale model of a hydrogen atom. You choose, for the nucleus, a small ball bearing with a radius of 1.
RoseWind [281]

Answer:

A)  x _electron = 0.66 10² m , B)   x _Eart = 1.13 10² m , C)  d_sphere = 1.37 10⁻² mm

Explanation:

A) Let's use a ball for the nucleus, the electron is at a farther distance the sphere for the electron must be at a distance of

Let's use proportions rule

                x_ electron = 0.529 10⁻¹⁰ /1.2 10⁻¹⁵ 1.5

               x _electron = 0.66 10⁵ mm = 0.66 10² m

B) the radii of the Earth and the sun are

               R_{E} = 6.37 10⁶ m

                tex]R_{Sum}[/tex] = 6.96 10⁸ m

                Distance = 1.5 10¹¹ m

                x_Earth = 1.5 10¹¹ / 6.96 10⁸  1.5

                x _Eart = 1.13 10² m

C) The radius of a sphere that represents the earth, if the sphere that represents the sun is 1.5 mm, let's use another rule of proportions

            d_sphere = 1.5 / 6.96 10⁸  6.37 10⁶

            d_sphere = 1.37 10⁻² mm

5 0
2 years ago
A sister spins her brother in a circle of radius R at angular speed wi. Then the sister decreases her angular speed
Igoryamba

Answer:

The change in the centripetal acceleration of the brother,

                               Δa = V₂²/R - V₁²/R

Explanation:

Given data,

A sister spins her brother in a circle of radius, R

The angular velocity of the brother, ω₁ = V₁/R

The angular velocity of the brother, ω₂ = V₂/R

The centripetal acceleration is given by the relation

                                 a = V²/R

Therefore change in the centripetal acceleration of the brother,

                              Δa = V₂²/R - V₁²/R                                    

6 0
2 years ago
You are provided with three polarizers with filters making angles of (A) 90 ​∘ ​​ , (B) 180 ​∘ ​​ and (C) −45 ​∘ ​​ with respect
irinina [24]

Answer:

Order of maximum transmission of the polarizer is A, C and B.

Solution:

As per the question:

For the first polarizer, the angle is quite insignificant:

(A) 90^{\circ}:

The light intensity after passing through the first polarizer is I_{o} and this intensity does not depend on the angle of the polarizer.

Consider 90^{\circ} with the vertical, the intensity is given by:

I = I_{o}cos^{2}90^{\circ}

I = I_{o}cos(2(45^{\circ})) = I_{o}(\frac{1+cos90^{\circ})}{2} = \frac{I_{o}}{2}

(B) 180^{\circ}:

Suppose the second polarizer is  45^{\circ} with the vertical.

Now, intensity through the second polarizer:

I' = Icos^{2}(\theta_{2} - \theta_{1}) = \frac{I_{o}}{2}cos^{2}(- 45 - 90)

I' =  \frac{I_{o}}{2}cos^{2}135^{\circ} = \frac{I_{o}}{4}

Now, if we consider the second polarizer to be 180^{\circ},

I' = \frac{I_{o}}{2}cos^{2}180^{\circ} = \frac{I_{o}}{2}cos^{2}(180^{\circ} - 90^{\circ}) = 0

(C) - 45^{\circ}:

Now,

Intensity through the third polarizer, if it is 180^{\circ} with the vertical:

I' = Icos^{2}(\theta_{2} - \theta_{1}) = \frac{I_{o}}{2}cos^{2}(180 - (- 45))

I' = \frac{I_{o}}{8}

5 0
2 years ago
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