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laiz [17]
2 years ago
6

An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucle

us of lead (charge +82e=+1.31×10−17C+82e=+1.31×10−17C). You may treat both objects as point charges. How much work would you have to do to move the electron to a distance 5.00×10−10m5.00×10−10m from the center of the lead nucleus
Physics
1 answer:
shtirl [24]2 years ago
3 0

Answer:

-9.45\times10^{-16} \text{ J}

Explanation:

According to Coulomb's law, the force of attraction between two point charges, q_1 and q_2, separated by a distance d is given by

F = k\dfrac{q_1q_2}{d^2}

k is a constant with a value of 9\times10^9\text{ F/m}.

When we substitute the values from the question,

F = (9\times10^9\text{ F/m})\dfrac{(-1.60\times10^{-19} \text{ C})\times(+1.31\times10^{-17}\text{ C})}{(1.00\times10^{-10}\text{ m})^2} = -1.89\times10^{-6} \text{ N}

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

W = F\times r

W = (-1.89\times 10^{-6} \text{ N})\times(5.00\times10^{-10}\text{ m}) = -9.45\times10^{-16} \text{ J}

This is negative because work is done on the electron, not by it.

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Materials have unique properties because each one is made up of different kinds of which particle?
inysia [295]

D. Atoms.

Explanation:

All the matter is made of elementary particles called "atoms".

Further, an atom is made of electrons, protons and neutrons. The electrons & protons are again made of the fundamental sub-particles, electrons (leptons) and the protons(quarks).

The classification of particles is shown in the figure attached


7 0
2 years ago
Read 2 more answers
A bird is flying in a room with a velocity field of . Calculate the temperature change that the bird feels after 9 seconds of fl
Korvikt [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The temperature change is \frac{dT}{dt} = 1.016 ^oC/m

Explanation:

From the question we are told that

   The velocity field with which the bird is flying is  \vec V =  (u, v, w)= 0.6x + 0.2t - 1.4 \ m/s

   The temperature of the room is  T(x, y, u) =  400 -0.4y -0.6z-0.2(5 - x)^2 \  ^o C

    The time considered is  t =  10 \  seconds

    The  distance that the bird flew is  x  =  1 m

 Given that the bird is inside the room then the temperature of the room is equal to the temperature of the bird

Generally the change in the bird temperature with time is mathematically represented as

      \frac{dT}{dt} = -0.4 \frac{dy}{dt} -0.6\frac{dz}{dt} -0.2[2 *  (5-x)] [-\frac{dx}{dt} ]

Here the negative sign in \frac{dx}{dt} is because of the negative sign that is attached to x in the equation

 So

       \frac{dT}{dt} = -0.4v_y  -0.6v_z -0.2[2 *  (5-x)][ -v_x]

From the given equation of velocity field

    v_x  =  0.6x

    v_y  =  0.2t

     v_z  =  -1.4

So

\frac{dT}{dt} = -0.4[0.2t]  -0.6[-1.4] -0.2[2 *  (5-x)][ -[0.6x]]    

substituting the given values of x and t

\frac{dT}{dt} = -0.4[0.2(10)]  -0.6[-1.4] -0.2[2 *  (5-1)][ -[0.61]]      

\frac{dT}{dt} = -0.8 +0.84 + 0.976  

\frac{dT}{dt} = 1.016 ^oC/m  

5 0
2 years ago
A spring stores 10. joules of elastic potential
Mekhanik [1.2K]
The answer would be . Since we are looking for the spring constant you would need to use the formula
PEs =  \frac{1}{2} k {x}^{2}
. Then you'd substitute, for PEs and x.
10j=1/2k(.20m^2).
Then solve. k=500n/m
6 0
2 years ago
Read 2 more answers
Heat is allowed to flow from the heat source of a heat engine at 425 K to a cold sink at 313 K. What is the efficiency of the he
olga2289 [7]
I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency. 

Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by
\eta = 1- \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the cold temperature
T_{hot} is the hot temperature

For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is
\eta=1- \frac{313 K}{425 K}=0.264 = 26.4 \%
3 0
2 years ago
Read 2 more answers
A motor does a total of 480 joules of work in 5.0 seconds to lift a 12-kilogram block to the top of a ramp. The average power de
stepan [7]
Power may be defined as the rate of doing work or the rate of using energy. <span> It is the amount of energy consumed per unit time. It is calculated as follows:

P = E / t
P = 480 / 5
P = 96 W <-----OPTION 3

Hope this answers the question. Have a nice day.</span>
7 0
2 years ago
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