Question

Light of wavelength 610 nm is incident on a slit of width 0.20 mm, and a diffraction pattern is produced on a screen that is 1.5 m from the slit. What is the distance of the second dark fringe from the center of the bright fringe>?

Answer 1

Answer:

distance of the second dark fringe from the center of the bright fringe is 0.92 cm

Explanation:

given data

wavelength = 610 nm = 610 × $10^{-9}$ m

slit of width = 0.20 mm = 0.20 × $10^{-3}$ m

distance between screen and slit = 1.5 m

solution

we apply here formula for second minima that is

L = $\frac{n \lambda D}{d}$   ...................1

and here for second minima n is 2

put here value we get

L = $\frac{2*610*10^{-9}*1.5}{0.20*10^{-3}}$    

L = 0.915 × $10^{-2}$ m

so distance of the second dark fringe from the center of the bright fringe is 0.92 cm