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Travka [436]
2 years ago
3

Suppose you start with 0.303 g of copper wire and faithfully follow the procedure. At the end you find that the copper dust weig

hs 0.309 g. Based on your understanding of the experimental procedure, offer at least two rational explanations for this apparent violation of the law of conservation of mass.
Chemistry
1 answer:
azamat2 years ago
3 0

Answer:

Hi, the given question has some missing parts as the experimental procedure has not been mentioned.

Explanation:

In general, violation of conservation of mass could be ascribed to following factors-

(1) Copper might be oxidized to copper oxide through aerial oxidation which has higher molar mass than metallic copper.

(2) Presence of moisture could lead to increase in mass. So proper drying is needed.

(3) As difference in mass arises at third decimal point therefore accurate weighing of sample is required during experiment.

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Alexxandr [17]
C2H6O + O2 ---> C2H4O2 + H2O

using the molar masses:-
24+ 6 + 16 g of C2H6O  produces 24 + 4 + 32 g C2H4O2    (theoretical)
 46 g produces 60g 

60 g C2H4O2 is produced from 46g C2H6O
1g      .     .................................46/60 g 
 700g     .................................    (46/60) * 700  Theoretically

But as the yield is only 7.5% 

the required amount is    ((46/60) * 700 ) / 0.075 =  7155.56 g 

=  7.156 kg to nearest gram.  Answer




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2 years ago
Write the balanced half-equation describing the oxidation of mercury to hgo in a basic aqueous solution. Please include the stat
Cloud [144]

Answer:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Explanation:

Hello,

In this case, mercury (II) oxide (HgO) is obtained via the reaction:

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Nonetheless, since it is a reaction carried out in basic solution, mercury's half-reaction only, must be:

Hg^0+2OH^-\rightarrow Hg^{2+}O+H_2O+2e^-

Thus, it is seen that OH ionis should be added due to the basic aqueous solution considering that 2 electrons are transferred from 0 to 2 in mercury.

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