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gulaghasi [49]
2 years ago
3

Given the balanced chemical equation: Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaNO3(aq) A 0.30 L of 0.20 M Ba(NO3)2(aq) is mixe

d with excess Na2SO4(aq) to make 200. g of solution in a coffee-cup calorimeter and allowed to react completely. The temperature of the solution rises from 25.2 ºC to 27.1 ºC. Answer the question in each step to find ∆Hrxn for this reaction. Cs,soln = 4.18 J/g ºC
Chemistry
1 answer:
VARVARA [1.3K]2 years ago
3 0

Answer:

∆Hrxn = -26467 J/mol

Explanation:

First, you need to know the reaction is exothermic because the solution temperature increases.

The heat of reaction, Q, is defined as:

Q = -C×m×ΔT

Where C is 4,18J/g°C; m is mass (200g); and ΔT is (27,1°C - 25,2°C = 1,9°C)

Q = 4,18J/g°C × 200g × 1,9°C

Q = -1588J

Now, moles of reaction are 0,30L × (0,20mol / L) = 0,06mol

That means ∆Hrxn is:

∆Hrxn: -1588J / 0,06mol = <em>-26467 J/mol</em>

<em></em>

I hope it helps!

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A 63.5 g sample of an unidentified metal absorbs 355 ) of heat when its temperature changes
insens350 [35]

0.208 is the specific heat capacity of the metal.

Explanation:

Given:

mass (m)  = 63.5 grams 0R 0.0635 kg

Heat absorbed (q) = 355 Joules

Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K

cp (specific heat capacity) = ?

the formula used for heat absorbed  and to calculate specific heat capacity of a substance will be calculated by using the equation:

q = mc Δ T

c = \frac{q}{mΔ T}

c = \frac{355}{63.5X 268.59}

 = 0.208 J/gm K

specific heat capacity of 0.208 J/gm K

The specific heat capacity is defined as  the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.

 

5 0
2 years ago
The nucleoside adenosine exists in a protonated form with a pKa of 3.8. The percentage of the protonated form at pH 4.8 is close
Natasha_Volkova [10]

Answer:

Ok:

Explanation:

So, you can use the Henderson-Hasselbalch equation for this:

pH = pKa + log(A^-/HA) where A- is the conjugate base of the acid. In other words, A- is the deprotonated form and HA is the protonated.

We can solve that

1 = log(A^-/HA\\) and so 10 = A^-/HA or 10HA = A-.  For every 1 protonated form of adenosine (HA), there are 10 A-. So, the percent in the protonated form will be 1(1+10) or 1/11 which is close to 9 percent.

6 0
2 years ago
A sample of gasoline contains various hydrocarbons, which comprise atoms of carbon, hydrogen, and oxygen. The hydrocarbons mix t
Naddika [18.5K]

Answer:

  • mixture
  • homogenous mixture  (of hydrocarbons)
  • compound

Explanation:

Mixture can be easily separated by physical methods. Homogeneity and heterogeneity of a mixture is determined by whether the components there in are in a single phase and evenly distributed or not.

A solution has a solute evenly dissolved in  solvent to form a liquid substance.

An element is the basic form of  substance which cannot be broke down into any other simpler unit.  

I hope this was helpful.

4 0
2 years ago
Which pair of compounds has the same empirical formula?
aleksandr82 [10.1K]

i think it's A. cause CH is 1:1 and if you reduce C2H2, the ratio would also be 1:1

5 0
2 years ago
Read 2 more answers
it takes 26.23 mL of a 1.008 M NaOh solution to neutralize a solution of an unknown monoprotic acid in 150.2 mL of solution. Wha
ASHA 777 [7]

Answer:

.176 M

Explanation:

set the number of moles of the base equal to the number of moles of acid.

(1.008 mol/L)(26.23 x 10^-3 L)=(150.2x10^-3 L)(x)

x = .176030892 mol/L

8 0
2 years ago
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