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elena-14-01-66 [18.8K]
2 years ago
3

According to a Pew Research Center poll, 70% of the 487 randomly selected adults aged 18-32 favor allowing gay and lesbian coupl

es to marry legally compared to 49% of the 833 randomly selected adults of all ages that favor such legalization, a difference of 21%. To compute the likelihood that you'd see such a difference or more just due to the luck of the draw, you first need to calculate the SE of the 2 samples a. In the young adult poll 70% favored gay marriage Calaulcte the SE for this percentage. Round your answer to 2 decimal places (Hint: first compute the SD of the box by estimating it to have 70% 1's) Submit Answer Tries 0/3 b. In the all adult poll 49% favored gay marriage. Calaucte the SE for this percentage. Round your answer to 2 decimal places Submit AnswerTries 0/3 C. The difference is 21%. Calculate the SE for this difference (Use your previously rounded answers for the SE's given above, and round the SE for the difference to 2 decimal places.) Submit AnswerTries 0/3 d. What is the value of the test statistic z?
Mathematics
1 answer:
lozanna [386]2 years ago
3 0

Answer:

ANSWER a):2.08%

ANSWER b) :1.73%

ANSWER c):0.35%

ANSWER d):7.77

Step-by-step explanation:

Solutiona:

p1^=0.7

n1=

SE=sqrt(p1^*(1-p1^)/n

=sqrt(0.70*(1-0.70)/487)

=0.0208

=0.0208*100

=2.08%

ANSWER:2.08%

Solutionb:

p2^=0.49

n2=833

SE2=sqrt(p*(1-p)/n

=sqrt(0.49*(1-0.0.49)/833)

=0.0173

=0.0173*100

SE2= 1.73%

ANSWER:1.73%

solutionc:

SE1-SE2=2.08-1.73=0.35%

ANSWER:0.35%

Solutiond:

H0:p1-p2=0.21

H1:p1-p2 >0.21

z=(p1^-p2^)/sqrt(p1^(1-p1)/n1+p2^(1-p2^)/n2

=0.21/sqrt(0.70*(1-0.70)/487+(0.49*(1-0.49)/833)

z=7.77

ANSWER:7.77

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