Answer:
C. effusion because there is a movement of a gas through a small opening into a larger volume
Explanation:
Effusion makes fluid/gas molecules move to the container with less pressure or larger volume. In diffusion, the movement should work two ways even though one side might receive more. But in effusion, the movement is rather one way.
This case shows how effusion work because its not the concentration that makes the balls moving to the bottom part of the container. No ball moving from bottom container to top either.
Answer:
The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass
Explanation:
2.23 M aqueous solution of NaCl means there are 2.23 moles of NaCl in 1000 mL of solution.
We know that density is equal to ratio of mass to volume.
Here density of solution is 1.01 g/mL.
So mass of 1000 mL solution = (
) g = 1010 g
molar mass of NaCl = 58.44 g/mol
So mass of 2.23 moles of NaCl = (
) g = 130.3 g
% by mass is ratio of mass of solute to mass of solution and then multiplied by 100.
Here solute is NaCl.
So % by mass of 2.23 M aqueous solution of NaCl = 
% = 12.90%
Answer:
The correct statements are given below
Explanation:
b Enoyl CoA isomerase an enzyme that converts cis double bonds to trans double bonds in fatty acid metabolism,bypasses a step that reduces Q,resulting in the higher ATP yield.
c Even chain fatty acids are oxidized to acetyl CoA in the beta oxidation pathway.
f The final round of beta oxidation foe a 13 carbon saturated fatty acid yields acetyl CoA and propionyl CoA a three carbon fragment.
<span>When two electrical charges, of
opposite sign and equal magnitude, are separated by a distance, a dipole is
established. The size of a dipole is measured by its dipole moment (</span>μμ). Dipole moment is measured in Debye
units, which is equal to the distance between the charges multiplied by the
charge (1 Debye equals 3.34×10−30Cm3.34×10−30Cm). The dipole moment
of a molecule can be calculated by Equation 1.11.1:
μ = qr
where
<span>
<span>μ⃗ μ→ is the dipole moment vector</span>
<span>qiqi is the magnitude of the ithith charge, and</span>
<span>r⃗ ir→i is the vector representing the position
of ithith charge.</span>
</span>
r = μ/q
<span>r = [0.838D(3.34×10−30 C⋅m/ 1D)]/ (1.6×10−19
C) *0.124
</span>
r = 1.41 x10^-10 m
Answer:
its height relative to some reference point, its mass, and the strength of the gravitational field
Explanation:
Gravitational energy is the potential energy associated with gravitational force, such as elevating objects against the Earth’s gravity. The potential energy due to elevated positions is called gravitational potential energy.
The factors that affect an object’s gravitational potential energy are the following; its height relative to some reference point, its mass, and the strength of the gravitational field it is in. For instance, consider a wallet lying on a table, it has less gravitational potential energy than the same wallet lying on top of a taller cupboard, and yet lesser gravitational potential energy than a heavier wallet lying on the same table.
If an object lies at a certain height above the Moon’s surface, it has less gravitational potential energy than the same object lying at the same height above the Earth’s surface because the Moon’s gravitational force is weaker.
