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GaryK [48]
2 years ago
7

How many moles of libr are contained in 347 g of water in a 0.175 m libr solution?

Chemistry
1 answer:
bonufazy [111]2 years ago
4 0
Molarity = number of moles of solute/Kg of solvent

Molarity is given in the problem as 0.175 m
Mass of solvent = 347 gm = 0.347 Kg

Therefore,
0.175 = number of moles of LiBr / 0.347
number of moles of LiBr = 0.175 x 0.347 = 0.060725 moles
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