It represents a decomposition reaction because one reactant breaks apart and forms two products.
Explanation:
The type of chemical reaction depicted by Jane represents a decomposition reaction because on reactant breaks apart and forms two products.
In this reaction XY breaks apart to form X and Y. This is a decomposition reaction.
XY → X + Y
- Decomposition or cracking is the formation of two or more products from a single reactant.
- The break down of a compound into individual atoms or molecules falls into this category.
- The extreme instability of a compound drives such a reaction.
- The products is usually stable or it can dissociate further till it is stable.
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Answer : The correct option is, the negative log of the hydroxide ion concentration.
Explanation :
pOH : It is defined as the negative logarithm of hydroxide ion concentration. It is a measure of the alkalinity of the solution.
Formula used :
![pOH=-log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D)
is the concentration of
ions.
When pOH is less than 7, the solution is alkaline.
When pOH is more than 7, the solution is acidic.
When pOH is equal to 7, the solution is neutral.
Answer;
1.6 kg.
Solution;
The density is 1.36 g/ml;
The volume is 1.25 qt
However; 1 qt = 946.35 ml
Mass is given by; density × volume;
= 1.25 qts × 946.25 ml/qt × 1.36 g/ml =1609 g
but; 1 kg = 1000 g
Hence the mass = 1609/1000 = 1.609 Kg or 1.61 (sig figs)
Answer:
6
Explanation:
You will see H6 and the H stands for helium and the 6 is how many of that atom is there
Answer: Option (e) is the correct answer.
Explanation:
A bond that is formed when an electron is transferred from one atom to another results in the formation of an ionic bond.
For example, NaBr will be an ionic compound as there is transfer of electron from Na to Br.
Whereas a bond that is formed by sharing of electrons is known as a covalent bond.
For example,
will be a covalent compound as there is sharing of electron between carbon and bromine atom.
Also, when electrons are shared between the combining atoms and there is large difference in electronegativity of these atoms then partial charges develop on these atoms. As a result, it forms a polar covalent bond.
For example, in a HBr compound there is sharing of electrons between H and Br. Also, due to difference in electronegativity there will be partial positive charge on H and partial negative charge on Br.
Thus, we can conclude that out of the given options HBr is the only compound that has polar covalent bonds.