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1 year ago

How many hydrogen atoms are in 11C2H6

Chemistry

2 answers:

sveticcg [70]1 year ago

6 0

The answer is six atoms

tresset_1 [31]1 year ago

5 0

Answer:

Explanation:

You will see H6 and the H stands for helium and the 6 is how many of that atom is there

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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N2O4(g) 2N

Amanda [17]

Answer : The correct option is, (a) 0.44

Explanation :

First we have to calculate the concentration of $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

Now we have to calculate the dissociated concentration of $N_2O_4$ .

The balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(aq)$

Initial conc. 1.0 M 0

At eqm. conc. (1.0-x) M (2x) M

As we are given,

The percent of dissociation of $N_2O_4$ = $\alpha$ = 28.0 %

So, the dissociate concentration of $N_2O_4$ = $C\alpha=1.0M\times \frac{28.0}{100}=0.28M$

The value of x = $C\alpha$ = 0.28 M

Now we have to calculate the concentration of $N_2O_4\text{ and }NO_2$ at equilibrium.

Concentration of $N_2O_4$ = 1.0 - x = 1.0 - 0.28 = 0.72 M

Concentration of $NO_2$ = 2x = 2 × 0.28 = 0.56 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.56)^2}{0.72}=0.44$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.44

8 0

1 year ago

BRAINLIESTTT ASAP!!!

Stels [109]

While I am not the brainliest I can certainly answer.

This was a chemical change because the chemical components were changed, a big giveaway to this was the fizzing, however the temperature rising was also another giveaway.

8 0

1 year ago

Read 2 more answers

2. The diagram below shows steps in the exothermic chemical reaction of bromomethane with

vovangra [49]

Answer:

Here's what I get

Explanation:

1. Balanced equation

HQ⁻ + CH₃-Br ⟶ HQ-CH₃ + Br⁻

(I must use HQ because the Brainly Editor thinks the O makes a forbidden word)

2. Mechanism

HQ⁻ + CH₃-Br ⟶[HQ···CH₃···Br]⁻⟶ HQ-CH₃ + Br⁻

A C B

The hydroxide ion attacks the back side of the carbon atom in the bromomethane (A).

At the same time as the Q-H bond starts to form, the C-Br bond starts to break.

At the half-way point, we have a high-energy intermediate (C) with partially formed C-O and C-Br bonds.

As the reaction proceeds further, the Br atom drops off to form the products — methanol and bromide ion (B).

3. Energy diagram

See the diagram below.

8 0

1 year ago

How many moles are in 6.5e23 atoms of Ne?

Savatey [412]

<h3>Answer:</h3>

1.1 mol Ne

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 6.5 × 10²³ atoms Ne

[Solve] moles Ne

<u>Step 2: Identify Conversion</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 6.5 \cdot 10^{23} \ atoms \ Ne(\frac{1 \ mol \ Ne}{6.022 \cdot 10^{23} \ atoms \ Ne})$
[DA] Divide [Cancel out units]: $\displaystyle 1.07938 \ mol \ Ne$