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Simora [160]
1 year ago
9

How many hydrogen atoms are in 11C2H6

Chemistry
2 answers:
sveticcg [70]1 year ago
6 0
The answer is six atoms
tresset_1 [31]1 year ago
5 0

Answer:

6

Explanation:

You will see H6 and the H stands for helium and the 6 is how many of that atom is there

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The acid-dissociation constant, ka, for gallic acid is 4.57 ⋅ 10-3. what is the base-dissociation constant, kb, for the gallate
LiRa [457]
Hello!

To determine the Kb of gallic acid is actually very simple. 

The dissociation reaction of Gallic Acid (HGal) is the following:

HGal+H₂O ⇄ H₃O⁺ + Gal⁻

The equation for converting from Ka to Kb is the following:

Ka*Kb=Kw \\  \\ Kb= \frac{Kw}{Ka}= \frac{1*10^{-14} }{4,57*10^{-3} }=2,19 * 10^{-12}

So, the Kb is 2,19*10⁻¹²

Have a nice day!
3 0
2 years ago
Read 2 more answers
Predict your observation if a magnesium ribbon is put in potassium hydroxide solution and tested with a lighted wooden splinter.
koban [17]

mg reacts with the acid and produce visible bubbles of hydrogen gas. they will produce audible pops as the hydrogen ignites. ... Hydrochloric acid is a corrosive liquid. Hydrogen gas is explosive.

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2 years ago
A sample of ammonia gas at 75°c and 445 mm hg has a volume of 16.0 l. what volume will it occupy if the pressure rises to 1225 m
ioda
In this kind of exercises, you should  use the "ideal gas" rules: PV = nRT
P should be in Pascal: 
445mmHg = 59328Pa
1225mmHg = 163319Pa

V should be in cubic meter:
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R = \frac{PV}{nT} = constant
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V2 = \frac{P1 V1}{P2} = \frac{445 0.016}{1225}
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7 0
2 years ago
Calculate the amount (in grams) of kcl present in 75.0 ml of 2.10 m kcl
Lera25 [3.4K]
V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
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C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
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74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
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:•)
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2 years ago
Which of the following statements is true?
Rom4ik [11]
I think that its D.
6 0
2 years ago
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