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zhuklara [117]
2 years ago
12

A professor, transferred from Toronto to New York, needs to sell his house in Toronto quickly. Someone has offered to buy his ho

use for $220,000, but the offer expires at the end of the week. The professor does not currently have a better offer but can afford to leave the house on the market for another month. From conversations with his realtor, the professor believes the price he will get by leaving the house on the market for another month is uniformly distributed between $210,000 and $235,000.
(a) If he leaves the house on the market for another month, what is the probability that he will get at least $225,000 for the house?
(b) If he leaves it on the market for another month, what is the probability he will get less than $217,000?
(c) What is the expected value and standard deviation of the house price if it is left in the market?
Mathematics
1 answer:
I am Lyosha [343]2 years ago
4 0

Answer:

(a) = 40%

(b) = 28%

(c) Expected value = $222,500

Standard deviation = $7,216.88

Step-by-step explanation:

This is a normal distribution with a = 210,000 and b =235,000

(a) The probability that he will get at least $225,000 for the house is:

P(X\geq 225,000) =1 -\frac{225,000-a}{b-a} =1-\frac{225,000-210,000}{235,000-210,000} \\P(X\geq 225,000) =0.4= 40\%

(b)The probability he will get less than $217,000 is:

P(X\leq 217,000) =\frac{217,000-a}{b-a} =\frac{217,000-210,000}{235,000-210,000} \\P(X\leq 217,000) =0.28= 28\%

(c) The expected value (E) and the standard deviation (S) are:

E=\frac{a+b}{2}=\frac{210,000+235,000}{2}\\ E=\$222,500\\S=\frac{b-a}{\sqrt{12}}=\frac{235,000-210,000}{\sqrt{12}}\\S=\$7,216.88

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Cameron buys 2.45 pounds of apples and 1.65 pounds of pears. Apples and pears each cost c dollars per pound. If the total cost a
Leto [7]

Answer:

2.45c + 1.65c = 4.12 + 0.75

Step-by-step explanation:

To write an equation to find the value for c, we need to declare what c is first.

c = price of fruit

2.45c + 1.65c = 4.12 + 0.75

Now we multiplied c to 2.45 and 1.65 and added them together, because whatever the value of c is will give us the equivalence of the sum of 4.12 + 0.75.

Now to check if the equation is right, let's solve for c.

2.45c + 1.65c = 4.12 + 0.75

4.1c = 4.87

Now to get the value of c, we divide both sides of the equation by 4.1.

\dfrac{4.1c}{4.1}=\dfrac{4.87}{4.1}

c = 1.19

Now let's substitute the value of c in the equation to see if we got it right.

2.45(1.19) + 1.65(1.19) = 4.12 + 0.75

2.92 + 1.96 = 4.87

4.87 = 4.87

Therefore concluding that the value of c is 1.19.

7 0
2 years ago
In a statewide soccer competition, 36 games were played. Each team participating in the competition played once with every other
Tomtit [17]

Answer:

9 teams

Step-by-step explanation:

If the total games played was 36 and no team played each other twice, we need to ensure there isn't any double counting.

36 = (n-1) + (n-2) + (n-3) ... + (n-(n-1))

using this knowledge, we can then count up:

1+2+3+4+5+6+7+8 = 36

If our highest number is 8, then we know there must be 9 teams, because no team can play themselves.

8 0
2 years ago
Read 2 more answers
n winter, the price of apples suddenly went up by \$0.75$0.75dollar sign, 0, point, 75 per pound. Sam bought 333 pounds of apple
RSB [31]
$1.21 is the original price per pound...i too am having trouble with figuring out how to setup the equation!!
5 0
2 years ago
There are two misshapen coins in a box; their probabilities for landing on heads when they are flipped are, respectively, .4 and
Leokris [45]

Answer:

E(X) = 6.0706

Step-by-step explanation:

1) Define notation

X = random variable who represents the number of heads in the 10 first tosses

Y = random variable who represents the number of heads in range within toss number 4 to toss number 10

And we can define the following events

a= The first coin has been selected

b= The second coin has been selected

c= represent that we have 2 Heads within the first two tosses

2) Formulas to apply

We need to find E(X|c) = ?

If we use the total law of probability we can find E(Y)

E(Y) = E(Y|a) P(a|c) + E(Y|b)P(b|c) ....(1)

Finding P(a|c) and using the Bayes rule we have:

P(a|c) = P(c|a) P(a) / P(c) ...(2)

Replacing P(c) using the total law of probability:

P(a|c) = [P(c|a) P(a)] /[P(c|a) P(a) + P(c|b) P(b)] ... (3)

We can find the probabilities required

P(a) = P(b) = 0.5

P(c|a) = (3C2) (0.4^2) (0.6) = 0.288

P(c|b) = (3C2)(0.7^2) (0.3) = 0.441

Replacing the values into P(a|c) we got

P(a|c) = (0.288 x 0.5) /(0.288x 0.5 + 0.441x0.5) = 0.144/ 0.3645 = 0.39506

Since P(a|c) + P(b|c) = 1. With this we can find P(b|c) = 1 - P(a|c) = 1-0.39506 = 0.60494

After this we can find the expected values

E(Y|a) = 7x 0.4 = 2.8

E(Y|b) = 7x 0.7 = 4.9

Finally replacing the values into equation (1) we got

E(Y|c) = 2.8x 0.39506 + 4.9x0.60494 = 4.0706

And finally :

E(X|c) = 2+ E(Y|c) = 2+ 4.0706 = 6.0706

6 0
1 year ago
Find the volume of a cone with a base radius of 3 cm and a height of 9 cm
katovenus [111]

The volume of a cone is 84.78 cm                

<u>Step-by-step explanation</u>:

<u>Given</u>:

radius = 3 cm and

height = 9 cm

<u>To Find</u>:

The Volume of a Cone

<u>Formula</u>:

The Formula for the volume of a cone is

V=πr2 *h/3

<u>Solution</u>:

V=πr2 *h/3

π value is 3.14

V= 3.14*(3)^2*9/3

V=3.14*9*3

V= 84.78 cm

Therefore the volume is 84.78 cm.

5 0
2 years ago
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